Answer:
78% nitrogen, 21% oxygen and about 1 percent argon
Explanation:
To make it easier, assume that we have a total of 100 g of a compound. Hence, we have 58.80g of xenon, 7.166g of oxygen, and 34.04g of fluorine.
Know we will convert each of these masses to moles by using the atomic masses:
58.8/131.3 = 0.45 mole of Xe
7.166/16 = 0.45 mole of O
34.04/19 = 1.79 mole of F
Now, we will divide all the mole numbers by the smallest among them and get the number of atoms in the compound:
Xe = 0.45/0.45 = 1
O = 045/0.45 = 1
F = 1.79/0.45 = 3.98 = 4
So, the empirical formula of the compound XeOF₄
Answer is: name of Sn(SO₄)₂ is tin(IV) sulfate or stannic sulfate.
Major oxidation numbers for tin are +2 and +4 (group 14 <span>of the </span>periodic table). In this chemical compond tin has oxidation number +4, besause sulfate has oxidation number -2 (2·(-2) = -4). Compound has neutral charge and it is <span>moderately water and acid soluble.</span>
Answer:
The answer is the letter A.
Explanation:
It is letter A because of Chlorine needs an electron to have a full shell. So, it will receive a negative one because it is gaining an electron. Potassium lost an electron because the element has to share the electron with Chlorine to balance its properties.
