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77julia77 [94]
3 years ago
8

When you walk, you push against the floor, and _________.

Chemistry
1 answer:
Taya2010 [7]3 years ago
7 0
When you walk, you push against the floor, and t<span>he floor pushes back against you.

Answer: B. The floor pushes back agaisnt you. 

Good luck with your studies, I hope this helps~!
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If z = 4.0 and y = 9.6, what is the value of x?
krok68 [10]

Answer:

The value of x will be "1.4".

Explanation:

The given values are:

y = 9.6

z = 4.0

As we know,

The relation between x, y and z is:

⇒ z = \frac{y}{x}

and,

⇒ x=\frac{y}{z}

On substituting the given values, we get

⇒    =\frac{5.6}{4.0}

⇒    =1.4

8 0
3 years ago
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A. Chloride ions (CI)

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3 years ago
The cation that has the same number of electrons (isoelectronic) as Ne is
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Ne is isoelectronic with Na+ ion.
4 0
3 years ago
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VladimirAG [237]

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A (H)

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6 0
3 years ago
A 100.0mL bubble of hot gases at 225 C and 1.80 atm escapes from an active volcano, what is the new volume of the bubble outside
Inessa05 [86]
<h3>Answer:</h3>

112.08 mL

<h3>Explanation:</h3>

From the question we are given;

  • Initial volume, V1 = 100.0 mL
  • Initial temperature, T1 = 225°C, but K = °C + 273.15

thus, T1 = 498.15 K

  • Initial pressure, P1 = 1.80 atm
  • Final temperature , T2 = -25°C

                                     = 248.15 K

  • Final pressure, P2 = 0.80 atm

We are required to calculate the new volume of the gases;

  • According to the combined gas law equation;

\frac{P1V1}{T1}=\frac{P2V2}{T2}

Rearranging the formula;

V2=\frac{P1V1T2}{T1P2}

Therefore;

V2=\frac{(1.80atm)(100mL)(248.15K)}{(498.15K)(0.80atm)}

V2=112.08mL

Therefore, the new volume of the gas is 112.08 mL

8 0
3 years ago
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