Answer:
0.0432 M H2SO4
Explanation:
First, we want to find the moles of MNaOH used. We know that Molarity x Liters = moles. 0.160M x 0.0210L = 0.00336 moles MNaOH
to find the moles of H2SO4, we can use a mol ratio.
0.00336mol MNaOH x (1Mol H2SO4 /2mol MNaOH)
= 0. 00168 mol H2SO4
I found the mol ratio by looking at the coefficients in front of the molecules I knew(MNaOH) and the molecule I needed to find(H2SO4)
then, to find Molarity, we do mol/Liters
0.00168 mol/ 0.0388L =. 0.0432 M H2SO4
You can convert mL to L by dividing by 1000
the significant figures of this problem is 3, so my final answer will also have 3 sig figs.
-70°C
Sink
little
hydrogen bonding
Explanation:
Completing the statements:
Water's boiling point would have been close to -70°C. Ice would sink in water. Water would release little heat to warm land during the winter. Ice is less dense than water because of the hydrogen bonding that forms a hexagonal structure in water.
The unique property of water is as a result of its hydrogen bonding. Water is a polar covalent compound. Like most covalent compound, water would have naturally had a very low boiling point.
The intermolecular forces all hydrogen bonding gives water its unique nature.
Hydrogen bond is formed by an attraction between hydrogen one water water molecule and more electronegative atom on another molecule usually oxygen, nitrogen and fluorine.
They form very strong intermolecular interaction responsible for the behavior of water.
The higher specific heat capacity of water is due to this bond. It absorbs a lot of heat and does not release them on time. This causes water release heat during winter.
Water has a hexagonal shape or structure linking each molecules.
learn more;
Hydrogen bonding brainly.com/question/10602513
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Answer:
Independent
Explanation:
Independent Variable is the volume of the object. Dependent Variable is the mass of the object. So it
Answer:
6 is the right answer I know cause I like science
Answer:
SCl₂
Explanation:
In order to know the empirical formula, we have to follow a series of steps.
Step 1: Divide each percentage by the atomic mass
S: 26.95/32.07 = 0.8403
Cl: 59.61/35.45 = 1.682
Step 2: Divide all the numbers by the smallest one.
S: 0.8403/0.8403 = 1
Cl: 1.682/0.8403 ≈ 2
The empirical formula of the compound is SCl₂.