Answer:
A and D takes much slower
Explanation:
Here, we want to select, out of the four given reactions, the one that is slower than the other two
The answers in these case are reactions 1 and 4 ( A and D)
The two reactions show what is called rust (as directly seen in reaction 4)
When we speak of rust, we simply mean a reaction that occurs over time
For example, non coated roofings of houses doesn’t get to change color at an instant
The color degradation that occurs is something that takes some time from the initial time they were used to roof the house
Hence, from these analogy, we can see that these reactions need an an external support to thrive or to come into existence
These external supports are natural forces and they contributing efforts occur over time and cannot be seen immediately
These reactions are thus ones that take much slower time than conventional laboratory reactions in the case of the formation of the precipitate or a reaction that requires a low flash point temperature such as that of black powder to produce such explosive effects
So in conclusion, what we are saying is that the two selected reactions are subjected to the availability of some conditions and may take time to manifest and these absolutely differentiates them from reactions that are spontaneous such as the one having an explosive effect or the other one leading to the formation of a precipitate which takes far less times
There is a key piece of information that we are missing.
we need the following:
Kb of water= 0.512
the change in boiling point (ΔTb) can be calculated using the following formula:
ΔTb= Kb x m
we already have Kb, but we need to determine the molality (m).
1) let's convert the grams of glucose to moles using the molar mass of it. The molecule formula of glucose is C₆H₁₂O₆.
molar mass C₆H₁₂O₆= (6 x 12.0) + (12 x 1.01) + (6 x 16.0)= 180 g/mol
2) let's determine the Kilograms of water.
info:
density of water= 1.0 g/ mL or 1 grams = 1 mL
1000 grams= 1 kilogram
3) let's plug in the values to solve for molality
finally, we can solve for change in boiling point.
ΔTb= Kb x m
ΔTb= (0.512) (0.545m)=
0.279°C
I believe that is condensation
The final volume of the gas is 73.359 mL
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Given :
A sample gas has an initial volume of 72.0 mL
The work done = 141.2 J
Pressure = 783 torr
The objective is to determine the final volume of the gas.
Since, the process does 141.2 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.
Converting the external pressure to atm; we have
External Pressure P:
= 783 torr ×
= 1.03 atm
The work done W =
The change in volume ΔV=
ΔV =
ΔV =
ΔV = 0.001359 L
ΔV = 1.359 mL
The initial volume = 72.0 mL
The change in volume V is ΔV = V₂ - V₁
- V₂ = - ΔV - V₁
multiply both sides by (-), we have:
V₂ = ΔV + V₁
= 1.359 mL + 72.0 mL
= 73.359 mL
Therefore, the final volume of the gas is 73.359 mL .
Learn more about volume here:
brainly.com/question/27100414
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Answer:
Further apart
Explanation:
a) It is because most of the volume of a gas is composed of the large amounts of empty space between the gas particles.
b) In gases molecular collisions transfer momentum between fluid.