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Sauron [17]
3 years ago
13

A reaction between which two reactants will consistently yield a salt that forms an acidic solution?

Chemistry
2 answers:
lesya [120]3 years ago
6 0

Answer:

A reaction between a strong acid and a weak base.

Explanation:

The conjugate acid of a weak base is a strong acid.

\underbrace{\hbox{H}_{3}\text{O}^{+}}_{\hbox{acid}} + \underbrace{\hbox{B}}_{\hbox{base}} =\underbrace{\hbox{BH}^{+}}_{\hbox{acid}} + \underbrace{\hbox{H}_{2}\text{O}}_{\hbox{acid}}

The reaction above is reversible, so we can write

\underbrace{\hbox{BH}^{+}}_{\hbox{acid}} + \underbrace{\hbox{H}_{2}\text{O}}_{\hbox{base}}\rightleftharpoons \underbrace{\hbox{H}_{3}\text{O}^{+}}_{\hbox{acid}} + \underbrace{\hbox{B}}_{\hbox{base}}

Thus, the solution of the salt will be acidic, because it produces hydronium ions.

Example;

Ammonium chloride is the salt of a strong acid (HCl) and a weak base (NH₃).

Solutions of NH₄Cl are acidic.



zhannawk [14.2K]3 years ago
5 0

Answer:

a strong acid and a weak base

Explanation:

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The following reactions can be used to prepare samples of metals. Determine the enthalpy change under standard state conditions
mamaluj [8]

Answer:

a) 62.1 kJ/mol

b) 2.82 kJ/mol

c) 270.91 kJ/mol

d) -851.5 kJ/mol

Explanation:

The enthalpy change for a reaction in standard conditions (ΔH°rxn) can be calculated by:

ΔH°rxn = ∑n*ΔH°f, products - ∑n*ΔH°f, reagents

Where n is the number of moles in the stoichiometry reaction, and ΔH°f is the enthalpy of formation at standard conditions. ΔH°f = 0 for substances formed by only a single element. The values can be found in thermodynamics tables.

a) 2Ag₂O(s) → 4Ag(s) + O₂(g)

ΔH°f, Ag₂O(s) = -31.05 kJ/mol

ΔH°rxn = 0 - (2*(-31.05)) = 62.1 kJ/mol

b) SnO(s) + CO(g) → Sn(s) + CO₂(g)

ΔH°f,SnO(s) = -285.8 kJ/mol

ΔH°f,CO(g) = -110.53 kJ/mol

ΔH°f,CO₂(g) = -393.51 kJ/mol

ΔH°rxn = [-393.51] - [-110.53 - 285.8] = 2.82 kJ/mol

c) Cr₂O₃(s) + 3H₂(g) → 2Cr(s) + 3H₂O(l)

ΔH°f,Cr₂O₃(s) = -1128.4 kJ/mol

ΔH°f,H₂O(l) = -285.83 kJ/mol

ΔH°rxn = [3*(-285.83)] - [( -1128.4)] = 270.91 kJ/mol

d) 2Al(s) + Fe₂O₃(s) → Al₂O₃(s) + 2Fe(s)

ΔH°f,Fe₂O₃(s) = -824.2 kJ/mol

ΔH°f,Al₂O₃(s) = -1675.7 kJ/mol

ΔH°rxn = [-1675.7] - [-824.2] = -851.5 kJ/mol

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3 years ago
Which of these properties of an unknown liquid can be found using a beaker, a hot plate, and a temperature probe?
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Answer:

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Solution is here,

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or, 45/91.3 = 343/ T2

or, T2= (343×91.3)/45

or, T2=695.9 K = (695.9-273)°C=422.9°C

5 0
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