Answer:
77.5°C
Explanation:
Data obtained from the question include the following:
Mass (M) = 100g
Heat (Q) = 1x10^3 J
Change of temperature (ΔT) =..?
Note: The specific heat capacity (C) of gold = 0.129 J/g°C
With the above information obtained from the question, we can obtain the change in temperature as follow:
Q = MCΔT
Divide both side by MC
ΔT = Q/MC
ΔT = 1x10^3 / (100 x 0.129)
ΔT = 77.5°C
Therefore, the change in temperature is 77.5°C
An example is just when they have a a group o numbers, for any reason, and they want to find the average of then all
an example being um idk...numbers resulting from an experiment trying to find different densitys or something and they wanted to find the average density
Answer:
55.18 L
Explanation:
First we convert 113.4 g of NO₂ into moles, using its molar mass:
- 113.4 g ÷ 46 g/mol = 2.465 mol
Then we<u> use the PV=nRT formula</u>, where:
- P = 1atm & T = 273K (This means STP)
- R = 0.082 atm·L·mol⁻¹·K⁻¹
Input the data:
- 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K
And <u>solve for V</u>:
Answer:
The student should weigh out 61.2g of ethanolamine [6.12 * 10]
Explanation:
In this question, we are expected to calculate the mass of ethanolamine needed to make 60.0ml of it given that the density of the ethanolamine in question is 1.02g/cm^3
Mathematically, it has been shown that mass = density * volume
Hence, by multiplying the density by the volume, we get the mass.
Now, from the question we can see that we have the values for the density and the volume. We now need to get the mass.
Since cm^3 is same as ml, we need not perform any conversion.
Hence, the needed mass is:
60 * 1.02 = 61.2g
<span>The two elements that constitute almost three fourths of the earth's solid surface are oxygen and silicon. Oxygen accounts for 46.6 percent of the Earth's crust, while silicon is 27.7 percent. The next more plentiful element on the Earth's crust is Aluminum.</span>
