Compounds in alcoholic beverages that enhance flavor and appearance but may contribute to hangover symptoms are called congeners.
<h3>Alcoholic beverages:</h3>
Congeners are compounds that add to the flavor, smell, and appearance of most alcoholic beverages. These substances may make hangover symptoms worse. Because they contain fewer congeners than whiskey, brandy, and red wine, clear alcoholic beverages like gin and vodka have less of a hangover-inducing effect.
The impact of ethanol, or the alcohol in your drinks, is the primary contributor to a hangover. It is a poisonous substance that acts as a diuretic in the body, which causes you to urinate more frequently and increases the likelihood that you will become dehydrated. The incidence and intensity of hangovers are both increased by congeners, substances created during the digestion and maturation of alcohol.
Learn more about congeners here:
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Answer:</h3>
1.93 g
<h3>
Explanation:</h3>
<u>We are given;</u>
The chemical equation;
2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l) ΔH = -3120 kJ
We are required to calculate the mass of ethane that would produce 100 kJ of heat.
- 2 moles of ethane burns to produce 3120 Kilo joules of heat
Number of moles that will produce 100 kJ will be;
= (2 × 100 kJ) ÷ 3120 kJ)
= 0.0641 moles
- But, molar mass of ethane is 30.07 g/mol
Therefore;
Mass of ethane = 0.0641 moles × 30.07 g/mol
= 1.927 g
= 1.93 g
Thus, the mass of ethane that would produce 100 kJ of heat is 1.93 g
This is a question similar to one wrestled with by Newton himself, who didn't understand why the planets didn't fall into each other. The reason satellites don't fly into space is because they are being pulled towards the planet by the planet's gravity.
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The limiting reactant is chlorine (Cl2).
<u>Explanation</u>:
Limiting reactant is the amount of product formed which gets limited by the reagent without continuing it.
2 Al + 3 Cl2 ==> 2 AlCl3 represents the balanced equation.
Number of moles Al present = 34 g Al x 1 mole Al / 26.98 g
= 1.260 g moles of Al
Number of moles Cl2 present = 39 g Cl2 x 1 mole Cl2 / 35.45 g
= 1.10 g moles of Cl2
Dividing each reactant by it's coefficient in the balanced equation obtains:
1.260 moles Al / 2 = 0.63 g moles of Al
1.11 moles Cl2 / 3 = 0.36 g moles of Cl2
The reactant which produces a lesser amount of product is called as limiting reactant.
Here the Limiting reactant is Cl2.
