Answer:
Distillation
Explanation:
Miscible solvents are separated from each other through a process called as Distillation. This technique works on the principle of difference in the boiling point of the solvents that are forming the miscible solution.
Example:
Water and Ethanol are two miscible solvents. They have different boiling points.
Ethanol = 78.37 °C
Water = 100 °C
In a experimental setup attached below, water and ethanol mixture is taken in a round bottom flask and heated on a hotplate. Ethanol having less boiling point than water boils first and evaporates. The Ethanol vapors are condensed as they passes through the condenser. In this way the ethanol is separated first and water having greater boiling point is left behind.
Answer:
1.209g of MgO participates
Explanation:
In this problem, we have 0.030 moles of MgO that participates in a particular reaction.
And we are asked to solve for the mass of MgO that participates, that means, we need to convert moles to grams.
To convert moles to grams we need to use molar mass of the compound:
<em>1 atom of Mg has a molar mass of 24.3g/mol</em>
<em>1 atom of O has a molar mass of 16g/mol</em>
<em />
That means molar mass of MgO is 24.3g/mol + 16g/mol = 40.3g/mol
And mass of 0.030 moles of MgO is:
0.030 moles MgO * (40.3g/mol) =
<h3>1.209g of MgO participates</h3>
Using the relationship M1V1 = M2V2 where M1 and M2 are the molar concentrations (mol/L or mmol/ml) and V1 and V2 are the volumes of the solutions, we can arrive at the following answer for the given problem:
<span>15.0M (L of stock solution) = 2.35M (0.25L) *all volumes were converted to liters.
L of stock solution = (2.35*0.25)/15.0
Therefore, 0.0392L or 39.17 ml of stock solution is needed. </span>
Answer:
- (0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄)
Explanation:
A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid.
Also, a buffer solution is a solution which resists changes in pH when acid or alkali is added to it.
- (0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄) when dissolved in 1 L H₂O will produce a buffer because NaH₂PO₄ is considered as weak acid while Na₂HPO₄ is its conjugate base. 2.
- (0.1 mol H₃O⁺ + 0.1 mol Cl⁻) is not a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid.
- (0.1 mol HCl + 0.1 mol NaoH) HCL is a strong acid and NaOH is a strong base so it will not form a buffer when dissolved in water.
- (0.1 mol H₃O⁺ + 0.1 OH⁻) is not a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid
- (0.1 mol NaCl+ 0.1 mol KCl) NaCL and KCL are salts so it will not form a buffer when dissolved in water.
So the right choice is
- (0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄)
Answer:
Option E)
Explanation:
<u />
<u>1. Write the solubility equation:</u>
- CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻
<u>2. Write the concentrations below the equation:</u>
- CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻
A - s s s
<u>3. Write the Ksp equation:</u>
- Ksp = [Ca²⁺] . [CO₃²⁻] ↔ the solid substances do not appear
<u>4. Solve the equation:</u>
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