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Marrrta [24]
2 years ago
15

Solve 6x + 3) = 21.

Mathematics
1 answer:
LiRa [457]2 years ago
8 0

Answer:

18x^2 - 9

Step-by-step explanation:

y = f(x)= 6x^3 - 9x + 4

dy/dx = d/dx(6x^3) - d/dx(9x) + d/dx (4)

=6.d/dx(x^3) - 9.d/dx (x) + d/dx. (4)

=6.3x^2 - 9.1 + 0 =18x^2 - 9

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The key word here is "or". If it's an OR question, you add the probabilities together. If it says "and", you multiply them together
As it is an OR question though, you add them. 
So: 
15 + 5 = 20%
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Step-by-step explanation:

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2 years ago
A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If
Blababa [14]

Answer: Our required probability is \dfrac{1}{2}

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = \dfrac{1}{3}

So, Probability of getting head from fair coin = \dfrac{1}{2}

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}

Hence, our required probability is \dfrac{1}{2}

No, the answer is not \dfrac{1}{3}

5 0
2 years ago
Find the mean, median, and mode for the data set below.<br> weights of books (oz): 10 9 9 14 13 11
ziro4ka [17]

Answer:

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Median: 10.5

Mode: 9

3 0
3 years ago
This season, the probability that the Yankees will win a game is 0.61 and the
zhannawk [14.2K]

The probability that the Yankees will lose when they score fewer than 5 runs is 17.16%.

<h3><u>Probability </u></h3>

Given that this season, the probability that the Yankees will win a game is 0.61 and the probability that the Yankees will score 5 or more runs in a game is 0.56, and the probability that the Yankees win and score 5 or more runs is 0.44, to determine what is the probability that the Yankees will lose when they score fewer than 5 runs the following calculation must be made:

  • 1 - 0.61 = 0.39
  • 1 - 0.56 = 0.44
  • 0.39 x 0.44 = X
  • 0.1716 = X

Therefore, the probability that the Yankees will lose when they score fewer than 5 runs is 17.16%.

Learn more about probability in brainly.com/question/11234923

#SPJ1

6 0
2 years ago
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