Copper(I) compounds in aqueous solutions are unstable and disproportionate:
Cu₂SO₄ = Cu + CuSO₄
Necessary for dissolution of non-aqueous solvent.
M(Cu₂SO₄)=223.16 g/mol
m(Cu₂SO₄)=14.1 g
v=0.250 L
n(Cu₂SO₄)=m(Cu₂SO₄)/M(Cu₂SO₄)
c=n(Cu₂SO₄)/v=m(Cu₂SO₄)/(vM(Cu₂SO₄))
c=14.1/(0.250*223.16)=0.253 mol/L
0.253 M
Answer:
B no observation pls mark me branilest
Good luck on this one brp
The molarity of a solution if it tale 12.0 grams of Ca(No3)2 is calculated as below
molarity = moles/volume in liters
moles = mass/molar mass = 12.0 g/ 164 g/mol = 0.073 moles
molarity is therefore = 0.073/0.105 = 0.7 M
