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Lady bird [3.3K]
3 years ago
15

Luke and Sian want to plant a vegetable garden in their yard. A soil testing kit measures the soil pH at 5.0, but the lettuce th

ey want to plant does best at a pH of 6.5. Should they add an acid or a base to the soil to make it the optimum pH for growing lettuce?
Chemistry
1 answer:
dexar [7]3 years ago
4 0

Answer:

So, Luke and Sian has to increase the pH of the soil by adding base to it.

Explanation:

The pH is defined as the negative logarithm of the hydrogen ion concentration in their aqueous solution.

pH=-\log[H^+]

  • With increase in hydrogen ion concentration the pH value decreases.
  • With decrease in hydrogen ion concentration the pH value increases.

The pH of the soil after testing it on a kit comes out be 5.0, but they both need pH of the soil to 6.5.

Comparison of pH of soil:

  =  5.0 < 6.5

= High hydrogen ion concentration > High hydrogen ion concentration

So, Luke and Sian has to increase the pH of the soil by adding base .Doing so will decrease the hydrogen ion concentration in the soil (where as addition of acid lower the pH of soil).

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6. Geologists in Egypt and Ethiopia are comparing rock samples from rocks
Tcecarenko [31]

Answer:

Both are different.

Explanation:

Both rocks are different from one another because both formed from different types of rocks. Rock A was formed from small pieces of rock while on the other hand, Rock B was formed from liquid  rock so they both have different sources of rocks from which they were formed. Forming at the same time does not show that they are similar to each other, it is their source which decides that they are similar or different.

4 0
3 years ago
When of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezing poi
Nesterboy [21]

The given question is incomplete. The complete question is:

When 282. g of glycine (C2H5NO2) are dissolved in 950. g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 282. g of ammonium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for ammonium chloride in X.

Answer:  the van't Hoff factor for ammonium chloride is 1.74

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point  

K_f = freezing point constant = ?

i = 1 ( for non electrolyte)

m= molality

8.2^0C=1\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of solute (glycine) = 75.07 g/mol

Mass of solute (glycine) = 282 g

8.2^0C=1\times K_f\times \frac{282g}{75.07g/mol\times 0.95kg}

K_f=2.07

ii) 20.0^0C=i\times \times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of solute (ammonium chloride) = 53.49 g/mol

Mass of solute (ammonium chloride) = 282 g

20.0^0C=i\times 2.07\times \frac{282g}{53.49g/mol\times 0.95kg}

i=1.74

Thus the van't Hoff factor for ammonium chloride is 1.74

4 0
3 years ago
How many carbons are present in the hydrocarbon 3-ethyl-2,3,4-trimethylpentane
fiasKO [112]
I would say there is 10 (2 in the ethyl group, 3 in the three methyl groups and 5 in the pent chain)
4 0
3 years ago
Potassium chloride (KCl) is sometimes used to treat low blood potassium levels. Calculate the concentration of a saturated solut
brilliants [131]
Molarity  is the most convenient way to express concentration.

Mathematically, molarity is expressed as \frac{\text{mass of solute(g)}}{\text{gram molecular weight X Volume of solution (l)}}

In present case,
mass of solute (KCl) = 36 g
molecular weight of KCl = 74.55 g/mol
volume of solution = 100 ml = 0.1 l

∴ Molarity = \frac{36}{74.55X0.1}
                 = 4.829 M
Thus, conc. of saturated KCl at 20 oC is 4.829 M 
7 0
3 years ago
A 45 kg box is sitting on a window ledge 2.0 m above the ground. What is the potential energy of the box?
Travka [436]

Answer:

<h3>The answer is 900 J</h3>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 45 × 10 × 2

We have the final answer as

<h3>900 J</h3>

Hope this helps you

5 0
3 years ago
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