2 years ago

After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.

Mathematics

1 answer:

Rainbow [258]2 years ago

5 0

Answer:

Step-by-step explanation:

We get 0.811 as our depreciating value because we take 18.9% and turn it into a decimal. Then, we subtract that from 1. If we did 0.189 instead, it would depreciate at a rate of 81.1% annually.

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Alinara [238K]

Answer:

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Rewrite the function by completing the square f(x)=x^2-14x+63

Veseljchak [2.6K]

Answer:

f(x) = (x - 7)² - 14

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Algebra I

Standard Form: ax² + bx + c = 0
Vertex Form: f(x) = a(bx - c)² + d
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Step-by-step explanation:

Step 1: Define

f(x) = x² - 14x + 63

Step 2: Rewrite

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2 years ago

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A limited-edition poster increases in value each year with an initial value of $18. After 1 year and an increase of 15% per year

Roman55 [17]

Answer:

The required equation is $y = 18(1.15)^x$ .

Step-by-step explanation:

Consider the provided information.

The Initial value of poster = $ 18

After 1 year amount of increase = $ 20.70

With the rate of 15% = 0.15

Let future value is y and the number of years be x.

$y = 18(1.15)^x$

Now verify this by substituting x=1 in above equation.

$y = 18(1.15)^1=20.7$

Which is true.

Hence, the required equation is $y = 18(1.15)^x$ .

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Answer:

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2 years ago