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Answer:
The Total amount of of 33 boxes of chocolates including taxes is $838.358
Step-by-step explanation:
Given as :
The sales tax rate for city = 4.306%
The sales tax rate for the state = 44%
Total number of boxes = 33
The price of each chocolates = $17.13
So , The price of 33 boxes of chocolates = $17.13 × 33
I.e The price of 33 boxes of chocolates = $565.29
Now total tax including state and city = 4.306% + 44% = 48.306 %
So, The tax amount paid for 33 boxes of chocolates = 48.306 % of $565.29
∴ The tax amount paid for 33 boxes of chocolates = 48.306 % × $565.29
= 0.48306× $565.29
= $273.068
∴ The Total amount of of 33 boxes of chocolates including taxes = $565.29 + $273.068 = $838.358
Hence The Total amount of of 33 boxes of chocolates including taxes is $838.358 . Answer
Hey!
To find the percentage increase, you must use this formula:
{(50 - 92 / 50] × 100 = 84%
So, the percent increase from 50 to 92 is: 84%.
Answer:
2: 90
3: 110
4. 130
5. 150
and so on.
Step-by-step explanation:
Answer:
A sample of 1068 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?
We need a sample of n.
n is found when M = 0.03.
We have no prior estimate of
, so we use the worst case scenario, which is 
Then






Rounding up
A sample of 1068 is needed.