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insens350 [35]
3 years ago
12

the quotient of two negative integers results in an integer. how does the value of the quotient compared to the value of the ori

ginal two integers?
Mathematics
2 answers:
hodyreva [135]3 years ago
8 0
First, the quotient is positive (since the multiplication or division of any two negative numbers is positive). Second, the relationship between the first two numbers (let's describe them as "a" and "b", these are just placeholders) and the quotient (we'll describe this as "c") is simply multiplication and division, as shown below:
if
          a/b =c
then
          a = b*c
          b = a/c
anastassius [24]3 years ago
6 0

Answer:

If a ÷ b = c, then other two relations are:

i) c.b = a

ii) b = a ÷ c

Step-by-step explanation:

Given: The quotient of two negative integers results in an integer.

Let "a" and "b" are the two integers.

a ÷ b = c, where "c" is the quotient which is also an integer.

From the above equation, we get

c times b = a, that is c.b = a

and

b = a ÷ c

<u>Example</u>

If a = 6, b = 2, then

a ÷ b = 6 ÷ 2 = 3

c.b = 3 times 2 = 6

b = a ÷ c

6 ÷ 3 = 2

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