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alina1380 [7]
4 years ago
9

All living organisms are composed of A. at least three cells. B. one or more cells. C. only one cell. D. at least 100 cells.

Chemistry
2 answers:
Strike441 [17]4 years ago
5 0
B. One or more cells
That is the answer I believe!
Tomtit [17]4 years ago
5 0
B. one or more cells
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Burning a compound of calcium, carbon and nitrogen in oxygen generates calcium oxide (CaO), carbon dioxide (CO2) and nitrogen di
Slav-nsk [51]

Answer:

CaCN₂

Explanation:

A compound of calcium, carbon and nitrogen CaₐCₓNₙ in oxygen will burning producing:

CaₐCₓNₙ + O₂ → aCaO + xCO₂ + nNO₂

Moles of the oxides CaO, CO₂, NO₂ are:

CaO: 3.106g ₓ (1 mole / 56.08g) = <em>0.0554 moles of CaO = moles of Ca</em>

CO₂: 2.439g ₓ (1mole / 44g) = <em>0.0554 moles CO₂ = moles C</em>

NO₂: 5.097g ₓ (1mole / 46g) = <em>0.111 moles NO₂ = moles N</em>

Empirical formula is the chemical formula that represents the simplest ratio of elements in a compound.

Having as basis 0.0554 moles (The lower number of moles):

0.0554 moles Ca / 0.0554 = 1 Ca

0.0554 moles C / 0.0554 = 1 C

0.111 moles N / 0.0554 = 2N

Thus, the compound CaₐCₓNₙ  has as empirical formula:

Ca₁C₁N₂ = <em>CaCN₂</em>

3 0
4 years ago
How many atoms are in 3.89 moles of Cu?
AleksandrR [38]

Answer:

2.34×10^24

Explanation:

N=n×Na

N=3.89×(6.02×10^23)

N=2.34×+0^24 atoms of Cu

3 0
4 years ago
How plants adapt to temperature variation
natita [175]
Answer: One major strategy by which plants adapt to temperature change is to decrease the degree of unsaturation of membrane lipids under high temperature and increase it under low temperature. ... This pattern of changes in membrane lipids was distinct from that occurring during slow alterations in temperature.

Explanation: I found this answer from goggle
7 0
3 years ago
If the molar mass of calcium hydroxide (Ca(OH)2) is 74.1 g/mol, how many grams of calcium hydroxide are required to prepare 2.00
Llana [10]

Answer:

88.92 grams of Ca(OH)₂ are required

Explanation:

Molarity means mol/L, so 0.6 M are the moles of solute in 1 L of solution.

In 2 L, we 'll have the double of moles, 1.2

Mol . molar mass = grams

1.2 mol . 74.1 g/m = 88.92 grams of solute

5 0
4 years ago
Atrazine is an herbicide widely used for corn and is a common groundwater pollutant in the corn-producing regions of the United
riadik2000 [5.3K]

Answer:

0.94

Explanation:

Let's assume that the total sample of the soil is 1 cm³; which has a porosity of 0.4 cm³; then the original sample of the soil will be 0.6 cm³

The mass  of the soil particles in 1 cm³ of soil + water = 0.75 g

The fraction of the total atrazine can be calculated by the expression;

Total atrazine =C_w(\frac{g}{mL})*V_w(mL)+C_{(soil)}(\frac{g}{soil})*M_{(soil)}(gsoil)

Also; C_{(soil)}(\frac{g}{soil})= K_{oc}(\frac{mL}{gOC})*f_{oc} (\frac{gOC}{gsoil})*C_w(\frac{g}{mL})

NOTE THAT: K_{oc}( \frac{mL}{gOC})=K_{oc}\frac{L}{kgOC}

Total atrazine can now be calculated as:

C_w*0.4+K_{oc}f_{oc}C_w*0.75 = \frac{C_{soil}*M_{soil}}{Total atrazine}

=\frac{K_{oc}f_{oc}C_w*M_{soil}}{C_w*0.4+K_{oc}f_{oc}C_w*0.75} = \frac{0.75*K_{oc}f_{oc}}{0.4+K_{oc}f_{oc}*0.75}

= \frac{10^{2.52}*0.025*0.75}{0.4+10^{2.52}*0.025*0.75}

= 0.94

Thus,the fraction of total atrazine that will be adsorbed to the soil = 0.94.

3 0
4 years ago
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