Question

Calculate AS per mole for the melting of Hg at -38°C, AH fus = 2.3 kJ/mol. J/mol K

Answer 1

Answer : The value of change in entropy for melting of Hg is 9.8 J/mol.K

Explanation :

Formula used :

$\Delta S=\frac{\Delta H_{fus}}{T_m}$

where,

$\Delta S$ = change in entropy

$\Delta H_{fus}$ = change in enthalpy of fusion = 2.3 kJ/mol

$T_m$ = melting point temperature = $-38^oC=273+(-38)=235K$

Now put all the given values in the above formula, we get:

$\Delta S=\frac{\Delta H_{fus}}{T_m}$

$\Delta S=\frac{2.3kJ/mol}{235K}$

$\Delta S=\frac{2.3\times 10^3J/mol}{235K}$

$\Delta S=9.8J/mol.K$

Therefore, the value of change in entropy for melting of Hg is 9.8 J/mol.K