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2 years ago

ASAP for brainlist first correct question

Chemistry

1 answer:

Ghella [55]2 years ago

8 0

The second law of thermodynamics states that in a reversible process, the entropy of the universe is constant, whereas in an irreversible process, such as the transfer of heat from a hot object to a cold object, the entropy of the universe increases

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Helium decays to form lithium. Which equation correctly describes this decay?

GrogVix [38]

Answer:

⁴He₂ → ⁴Li₃ + ⁰e₋₁.

Explanation:

Helium decays with the release of an electron to form a lithium nucleus.

The number of nucleons is the same on both sides of the equation.

A neutron decays to form a proton with the release of an electron.

The atomic number increases from 2 to 3 while the atomic mass number stays the same at 4 nucleons.

8 0

3 years ago

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The electron

LekaFEV [45]

The electron B. is the smallest part of an atom.

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2 years ago

1. A student attempts to make a saline solution by adding salt to water. How much water did

dexar [7]

111.1 mL of water

Explanation:

Weight per volume concentration (w/v %) is defined as

weight per volume concentration = (mass of solute (g) / volume of solution (mL)) × 100

volume of solution = (mass of solute × 100) / weight per volume concentration

volume of solution = (1 × 100) / 0.9 = 111.1 mL

volume of water = volume of solution = 111.1 mL

Learn more about:

weight per volume concentration

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8 0

2 years ago

Elimination of the pharmaceutical IV antibiotic gentamicin follows first-order kinetics. If the half-life of gentamicin is 1.5 h

Genrish500 [490]

Explanation:

The given data is:

The half-life of gentamicin is 1.5 hrs.

The reaction follows first-order kinetics.

The initial concentration of the reactants is 8.4 x 10-5 M.

The concentration of reactant after 8 hrs can be calculated as shown below:

The formula of the half-life of the first-order reaction is:

$k=\frac{0.693}{t_1_/_2}$

Where k = rate constant

t1/2=half-life

So, the rate constant k value is:

$k=\frac{0.693}{1.5 hrs}$

The expression for the rate constant is :

$k=\frac{2.303}{t} log \frac{initial concentration}{concentration after time "t"}$

Substitute the given values and the k value in this formula to get the concentration of the reactant after time 8 hrs is shown below:

$\frac{0.693}{1.5 hrs} =\frac{2.303}{8 hrs} x log \frac{8.4x10^-^5}{y} \\ log \frac{8.4x10^-^5}{y} =1.604\\\frac{8.4x10^-^5}{y}=10^1^.^6^0^4\\\frac{8.4x10^-^5}{y}=40.18\\y=\frac{8.4x10^-^5}{40.18} \\=>y=2.09x10^-^6$

Answer: The concentration of reactant remains after 8 hours is 2.09x10^-6M.

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2 years ago

Measure the mass of a truckful of grain, use:

Nimfa-mama [501]

Answer:

tons

Explanation:

8 0

2 years ago

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