Answer:
0.164541341 g H2
Explanation:
1) Convert grams to moles by dividing by RMM of Magnesium (24.31g).
2g Mg * (1 mol Mg / 24.31 g Mg) = 0.082270671 mol of Mg
2) Use the balanced equation's ratio of 1 mol Mg: 1 mol H2.
0.082270671 mol of Mg = 0.082270671 mol of H2
3) Convert the mol of H2 back into grams by multiplying by H2's RMM (2 g).
0.082270671 mol of H2 * 2 g H2 = 0.164541341 g H2
* Answer can be rounded to your liking *
Answer:
True
Explanation:
Volume is measured in "cubic" units. The volume of a figure is the number of cubes required to fill it completely, like blocks in a box. Volume of a cube = side times side times side. Since each side of a square is the same, it can simply be the length of one side cubed.
Answer:

Explanation:
<em>Specific Heat:</em><em> </em>The specific Heat of any material is the heat absorbed or evolved by the material to raise or fall it's temperature by 1°C per unit mass of the material.
The heat absorbed or evolved (Q) is directly proportional to the mass of substance(m) and rise or fall of temp(∆T)
The general formula for specific heat is,

Where
- s is specific heat,
- Q is the Heat absorbed or evolved
- m is mass of substance
- & ∆T is change is temperature
<em>Now coming to your question,</em>
<em>The specific heat of Aluminium is 897 J/kg °C</em>
<em>The specific heat of Aluminium is 897 J/kg °C& specific heat of methanol is 2450 J/kg ° C</em>
The definition states that, <u>if the specific heat would be more, more amount of heat will be required for per unit change in temperature.</u>
The specific heat of Aluminium is 897 J/kg °C which means for one kilogram aluminium, 897 Joule energy is required to change it's temperature by 1°C & Similarly for one kilogram methanol 2450 joule energy is required.
Hence, the correct answer would be methanol!
<em><u>learn more about specific heat here,</u></em>
<em><u>brainly.com/question/27365354</u></em>
<em><u>brainly.com/question/27598037</u></em>

all i really know is that STP (standard temperature and pressure) represents conventional conditions established by IUPAC with T = 273.15 K, P = 1 atm . Now putting these values of temperature and pressure at STP, we can calculate easily volume occupied by 1 mol of gas and which comes out to be 22.4 L. hope this helps
Given -
T = 450K
∆H = 3000J
∆S = 4J/K
Using formula
∆G = ∆H - T∆S
∆G = 3000- 4*450
∆G = 1200 Joule
∆G is positive so the reaction is non spontaneous!