Question

Y= 9x + 7 over 3 rewrite in standard form

Answer 1

Subtract 9x from its side and move it over, -9x+y=7/3 should be your answer, hope i helped

Answer 2

Answer:

$3x-1y=-\frac{7}{3}$

Step-by-step explanation:

We've been given the equation $y=\frac{9x+7}{3}$

In order to bring it in the standard form we must write it as Ax + By = C

First, we need to split and divide both the terms of the numerator by 3 on the right side

$y=\frac{9x}{3}+\frac{7}{3}$

Simplifying $\frac{9}{3}$, we get 3

$y=3x+\frac{7}{3}$

Subtract $\frac{7}{3}$ from both side

$y-\frac{7}{3}=3x+\frac{7}{3}-\frac{7}{3}$

Cancel out $+\frac{7}{3}$ and $-\frac{7}{3}$ from the right side

$y-\frac{7}{3}=3x$

Subtract y from both sides

$y-\frac{7}{3}-y=3x-y$

Cancel out y and -y on the left side

$-\frac{7}{3}=3x-y$

y is written as 1y

$-\frac{7}{3}=3x-1y$

Flip the sides

$3x-1y=-\frac{7}{3}$