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lukranit [14]
3 years ago
5

A ranch owner has 18 bales of hay to distribute in 3 cow pastures and 3 horse pastures. He wants each cow pasture to have the nu

mber of bales of hay and each horse pasture to have the same number of bales of hay. He wants at least 1 bale of hay in each pasture. How many different ways can the hay be disrupted among the pastures?
Mathematics
1 answer:
Ivahew [28]3 years ago
7 0

First way: 1 bale in each cow pasture and 5 bales in each horse pasture.

Second way: 2 bales in each cow pasture and 4 bales in each horse pasture.

Third way: 3 bales in every pasture.

Fourth way: 4 bales in each cow pasture and 2 bales in each horse pasture.

Fifth way: 5 bales in each cow pasture and 2 bale in each horse pasture.

There are 5 different ways.

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Paha777 [63]
Since the graph is a linear function, we're going to use the slope formula solve this: 

Note I am replacing m with k
k= \frac{ y_{2}- y_{1} }{ x_{2}- x_{1} }

Inserting 2 points from the graph, let's use (1,8) and (2,16).

\frac{16-8}{2-1}



k=8



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2 years ago
Two plants, plant A and B, are being grown in a science experiment. Plant A is 6 cm tall and growing at a rate of 4 cm/day. Plan
Irina18 [472]
By the second day of growth
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3 years ago
Can a triangle be drawn with the following angle measures? Why or why not?<br> 50°, 70°, 70°
Viefleur [7K]

no, the 3 angles of a triangle need to equal 180 degrees

70 +70 +50 = 190 degrees so it cant be a triangle.

4 0
3 years ago
Read 2 more answers
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
2 years ago
Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 90.5 N , Jill pul
Radda [10]

Answer:

Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.

Step-by-step explanation:

We find the components of the forces in x-y-z

Force of  Jack in z   =F₁z=90.5 N in direction (+z)

Force of  Jill  in x     = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of  Jill  in y     =F₂y=-82.3*sin45°=   + 58.19 N (+y)

Force of  Jane  in x  =F₃x=125*cos45°=   + 88.4 N (+x)

Force of  Jane  in y   =F₃y=125*sin45°=   + 88.4  N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N  (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2}   }

F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2}   }

F_{n} = 174.9 N

7 0
3 years ago
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