<span>(-5w^10+10w^8+5w^6)/(5w^5)
to divide we can factor out 5w^5 from the numerator
=[5w^5(-w^5+2w^3+w)]/(5w^5)
5w^5 will cancel out to have
=(-w^5+2w^3+w)
Hence
Answer:</span>(-w^5+2w^3+w)<span>
</span>
The sum is 10s^2t-5st^2. With two separate sections it’s a binomial, and the sum of the powers of the variables is 2+1=3, it has a degree of 3.
Answer:
Assume the pair of dice are fair; if not, all bets are off!
Color one die green (G) and the other one red (R). There are 36 possibilities in throwing one green and one red die, eg (G1, R1), (G1, R2), etc; (G2, R1), (G2, R2), etc; etc; (G6, R1), (G6, R2), etc.
In the set of possible numbers from throwing a die, there are only 3 possibilities that sum to to 4: (G1, R3), (G2, R2), (G3, R1).
So the answer is 3/36, or one-twelfth.
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