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Jet001 [13]
3 years ago
12

A theory is a ____.

Chemistry
1 answer:
zepelin [54]3 years ago
6 0
A . well test explanation for a broad set of observations.
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What do these two changes have in common? Shaking up salad dressing. Adding dish soap to water in a sink
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I think it’s a maybe hope this helps
4 0
3 years ago
If motor bike travels 2.4 km in 5 min find it average velocity?​
Genrish500 [490]

Answer:

28.8km/h

Explanation:

Change the 5min to hours.

=5/60 =0.0833hrs

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2.4/0.0833

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3 0
3 years ago
23. Using the periodic table, what is the oxidation number of:
Aloiza [94]

Answer:

a. +2

b. +3

c. -1

Explanation:

The typical oxidation states can be determined from the periodic table based on the number of valence electrons an atom has.

a. Calcium belongs to group 2A, meaning it has 2 valence electrons and, therefore, would have an oxidation state of +2 in compounds.

b. Aluminum is in group 3A, meaning it has 3 valence electrons and would have an oxidation state of +3 in compounds when the 3 electrons are lost.

c. Fluorine would become fluorine if it gained 1 additional electron to achieve an octet, so its oxidation state would be -1.

8 0
3 years ago
When convex mirrors are used for security purposes, the images they form
konstantin123 [22]

Answer:false

Explanation:

3 0
3 years ago
F2 is light yellow/colorless in hydrocarbon solvent. I2 is pink. If a student combines fluorine water with NaI (sodium iodide) i
Tamiku [17]
F₂ + 2 NaI → 2 NaF + I₂
<span>It is given that F₂ is light yellow / colorless in hydrocarbon solvent. The student combines Fluorine water with NaI in water. Then student adds pentane in the mixture of F₂ and NaI. After dissolution, solution was observed and a colorless pentane layer was seen. Alkanes are unreactive in nature. The C-H bond in alkane is difficult to break. whereas, F₂ is very reactive and reacts vigorously with alkanes in presence of light by free radical mechanism.It is given that the color of the solution is nearly colorless. F₂ when present in hydrocarbon solvent is light yellow/ colorless/ nearly colorless. Hence, F₂ is not reacting with hydrocarbon and there is no reaction taking place (No F</span>₂ is present<span>)</span>
5 0
3 years ago
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