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klio [65]
4 years ago
8

Pls look at the photo above, thanks

Physics
1 answer:
frosja888 [35]4 years ago
4 0
V=s/t. All you need to do is
s=v×t=330×1.8
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To pull a 50 kg crate across a horizontal frictionless floor, a worker applies a force of 210 N, directed 20° above the horizont
tangare [24]

Answer:

Explanation:

Given that,

A crate of mass M = 50kg

The crate is pulled along an horizontal floor by a string at an angle

Force pulling the crate

F = 210N

Angle θ = 20° to the horizontal

Distance moved by crate d=3m

A. Work done by force

W = FdCosθ

W = 210 × 3 × Cos20

W = 592J

B. Work done by Gravitational force?

Work is define as the dot product of force and displacement in the direction of the force.

Since the gravitational force does not cause the crate to move any distance downward

Then,

W(gravity) = mg×d

distance d=0

W(gravity) = 0 J

C. Work done by normal?

Since, the normal force did not cause the crate to move upward by any distance

Then,

W(normal) = 0J

D. The total workdone?

The only workdone on the crate is by the person

Then, the total workdone is the workdone by the person

W = 592 J

4 0
3 years ago
What type of image is formed by a lens if m = -0.6?
DaniilM [7]

Answer:

Real and inverted

Explanation:

Magnification of a lens is defined as the ratio of the height of the image to the height of the object.

m=\dfrac{h'}{h}

Where

h' is the height of image

h is the height of the object

It is also defined as the ratio of image distance to the object distance.

m=\dfrac{-v}{u}

Here, m = -0.6

Negative sign shows the image is inverted. So, the formed image will be real and inverted.

7 0
4 years ago
Read 2 more answers
A 2.00-kg block is pushed against a spring with negligible mass and force constant k = 400 N/m, compressing it 0.220 m. When the
marin [14]

Answer:

0.82052 m

Explanation:

potential energy of spring = kinetic energy

=> 0.5kx^2 = 0.5mv^2

=> v=\sqrt{\frac{kx^2}{m} }

v=\sqrt{\frac{400\times 0.220^2}{2} }

v= 3.11127 m/s

angle = 37°

thus height = distance×sin(37) = D×0.60182

Also,

m×g×h = 0.5×m×v^2

=> 2×9.8×D×0.60182 = 0.5×2×3.11127×3.11127

=> D = 0.82052 m

4 0
3 years ago
When and where is the bar graph used?
ira [324]
<span>bar graphs are used to compare things between different groups or to track changes over time</span>
4 0
3 years ago
Read 2 more answers
A 0.300 kg mass is attached to
scoundrel [369]

Answer:

0.144 J

Explanation:

From the question above,

Total elastic energy of the spring = Kinetic energy of the spring + potential energy of the spring

E' = E.k+Ep...................... Equation 1

Ek = E'-Ep......................... Equation 2

Where E' = total elastic energy, E.k = kinetic energy, E.p = potential  energy.

E'  = 1/2ke² = 1/2(26.6)(0.12²) = 0.19152 J.

Ep = 1/2ke² = 1/2(26.6)(0.06²)

Ep = 0.04788 J

Therefore,

Ek = 0.19152-0.04788

Ek = 0.144 J

8 0
3 years ago
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