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klio [65]
3 years ago
8

Pls look at the photo above, thanks

Physics
1 answer:
frosja888 [35]3 years ago
4 0
V=s/t. All you need to do is
s=v×t=330×1.8
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Two ropes have equal length and are stretched the same way. The speed of a pulse on rope 1 is 1.4 times the speed on rope 2. Par
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Answer:

m1/m2 = 0.51

Explanation:

First to all, let's gather the data. We know that both rods, have the same length. Now, the expression to use here is the following:

V = √F/u

This is the equation that describes the relation between speed of a pulse and a force exerted on it.

the value of "u" is:

u = m/L

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V1 = √F/u1 (1)

rod 2:

V2 = √F/u2 (2)

Now, let's express V1 in function of V2, because we know that V1 is 1.4 times the speed of rod 2, so, V1 = 1.4V2. Replacing in the equation (1) we have:

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1.4(√F/u2) = √F/u1 (4)

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1.96F = F*u2/u1

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1.96m1 = m2

m1/m2 = 1/1.96

m1/m2 = 0.51

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3 years ago
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