Answer: 2940 J
Explanation: solution attached:
PE= mgh
Substitute the values:
PE= 10kg x 9.8 m/s² x 30 m
= 2940 J
A small rubber ball is launched by a compressed-air cannon from ground level with an initial speed of 17.3 m/s directly upward.
1 answer:
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You have not provided the diagram, therefore, I cannot provide an exact answer.
However, I will try to help by explaining how to solve this problem.
When light moves from air to glass:
1- part of the light is reflected back into the air where the angle of incidence is equal to the angle of reflection
2- part of the light enters the water and refracts. The angle of refraction can be calculated using Snell's law.
In a diagram, the reflected ray would be the one getting back into air while the refracted ray would be the one entering the water.
You can check the attached diagram for further illustrations.
Hope this helps :)
However, I will try to help by explaining how to solve this problem.
When light moves from air to glass:
1- part of the light is reflected back into the air where the angle of incidence is equal to the angle of reflection
2- part of the light enters the water and refracts. The angle of refraction can be calculated using Snell's law.
In a diagram, the reflected ray would be the one getting back into air while the refracted ray would be the one entering the water.
You can check the attached diagram for further illustrations.
Hope this helps :)