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4 years ago

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A jet taxiing down the runway receives word that it must return to the gate. The jet is traveling 37.6 m/s when the pilot receiv

es the message. What is the acceleration of the plane if it takes the pilot 5.37 s to bring the plane to a halt ?

1 answer:

IrinaVladis [17]4 years ago

5 0

Answer:

7 m/s^2

Explanation:

Given that the jet is traveling 37.6 m/s when the pilot receives the message.

And it takes the pilot 5.37 s to bring the plane to a halt.

Acceleration of the plane can be calculated by using first equation of motion

V = U - at

Since the plane is going to stop, the final velocity V = zero.

And the acceleration will be negative

Substitute all the parameters into the formula

0 = 37.6 - 5.37a

5.37a = 37.6

Make a the subject of formula

a = 37.6 / 5.37

a = 7.0 m/s^2

Therefore, the acceleration of the plane to bring the plane to a halt is 7 m/s^2

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3 years ago

Using the midpoint and the distance formulas, calculate he coordinate of the midpoint and the length of the segment.

arsen [322]

Answer:

Explanation:

Formula to calculate the distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is,

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Therefore, length of CD having coordinates C(3,1) and D(3, 3),

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7 0

3 years ago

Light that has a wavelength of 600 nm strikes a metal surface, and a stream of electrons is ejected from the surface. If light o

Anni [7]

Answer:

The maximum kinetic energy of the electrons emitted from the surface will be greater.

Option 3 is correct.

Explanation:

Given that,

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Using formula of energy

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$E=h\dfrac{c}{\lambda}$

Put the value into the formula

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Put the value into the formula

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So, E₂>E₁

Hence, The maximum kinetic energy of the electrons emitted from the surface will be greater.

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3 years ago

At an outdoor market, a bunch of bananas is set on a spring scale to measure the weight. The spring sets the full bunch of banan

Elina [12.6K]

Answer:

2.67kg

Explanation:

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$v_{max}=\omega A............(1)$

where $\omega$ is the angular velocity and A is the amplitude.

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$\omega=\sqrt{\frac{k}{m}}.................(2)$

where k is the force constant of the spring and m is the loaded mass.

We can make $\omega$ the subject of formula in equation (1) as follows;

$\omega=\frac{v_{max}}{A}.................(3)$

We then combine equations (2) and (3) as follows;

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According to the problem, the following are given;

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$\frac{1.92}{0.21}=\sqrt{\frac{223}{m}}$

$9.143=\sqrt{\frac{223}{m}}$

Squaring both sides, we obtain the following;

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3 years ago

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Delvig [45]

Answer:(c)

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3 years ago