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notsponge [240]
4 years ago
9

How must of the roller coaster's kinetic and/or potential energy is in each of the points. For each point, pick one option. (Sor

ry for the report, I found a mistake in my question and could not edit.)
Point A:
a. 1/2 Potential Energy, 1/2 Kinetic Energy
b. 1/2 Potential Energy, 0 Kinetic
c. 100 Potential Energy

Point B:
a. 1/4 Potential, 3/4 Kinetic
b. 100 Kinetic, 0 Potential
b. 1/2 Potential, 1/2 Kinetic

Point C:
a. 1/2 Potential, 1/2 Kinetic
b. 3/4 Potential, 1/4 Kinetic
c. 100 Potential, 0 Kinetic

Physics
1 answer:
labwork [276]4 years ago
3 0

Answer

  1. Point A-
  2. Point B-
  3. Point C- 100 Potential, 0 Kinetic

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Discuss the advantages and disadvantages of series circuits compared to parallel circuits. Give an example of where each type of
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3 years ago
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a stone is thrown horizonttaly from a cliff of a hill with an initial velocity of 30m/s it hits the ground at a horizontal dista
ELEN [110]

Answer:

a) Time = 2.67 s

b) Height = 35.0 m

Explanation:

a) The time of flight can be found using the following equation:

x_{f} = x_{0} + v_{0_{x}}t + \frac{1}{2}at^{2}   (1)

Where:

x_{f}: is the final position in the horizontal direction = 80 m

x_{0}: is the initial position in the horizontal direction = 0

v_{0_{x}}: is the initial velocity in the horizontal direction = 30 m/s

a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)

t: is the time =?  

By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:  

t = \frac{x_{f}}{v_{0}} = \frac{80 m}{30 m/s} = 2.67 s

b) The height of the hill is given by:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

Where:

y_{f}: is the final position in the vertical direction = 0

y_{0}: is the initial position in the vertical direction =?

v_{0_{y}}: is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)            

g: is the acceleration due to gravity = 9.81 m/s²

Hence, the height of the hill is:

y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m  

I hope it helps you!

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