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Lubov Fominskaja [6]
4 years ago
13

which term refers to energy derived from heat inside the Earth ? a) geothermal energy b) solar energy c) fossil fuel d) volcanic

energy
Physics
1 answer:
Katyanochek1 [597]4 years ago
4 0
The answer is a) geothermal energy. I may be wrong, sorry!
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Why is it important for a muscle to be attached to a fixed origin at one end and a moving insertion at the other? Discuss how th
vlabodo [156]
Muscles function only by contracting. This makes it necessary for one end of the muscle to be fixed and the other mobile.
Take the bicep for example.
Its origin is at the shoulder and its two heads connect to the bones of the forearm, the radius and ulna.
Now, had the muscle not been fixed at one end, and contracted, it would pull both our shoulder and forearm together resulting in an ineffective movement. The desired motion is to lift the forearm (proximal and distal movement) which can only be achieved if the bicep is fixed at the shoulder and allowed to move at the forearm.
6 0
3 years ago
A block whose weight is 45 N rests on a horizontal table. A horizontal force of 36 N is applied to the block. The coefficient of
riadik2000 [5.3K]

Answer:

1.5 m/s²

Explanation:

For the block to move, it must first overcome the static friction.

Fs = N μs

Fs = (45 N) (0.42)

Fs = 18.9 N

This is less than the 36 N applied, so the block will move.  Since the block is moving, kinetic friction takes over.  To find the block's acceleration, use Newton's second law:

∑F = ma

F − N μk = ma

36 N − (45 N) (0.65) = (45 N / 9.8 m/s²) a

6.75 N = 4.59 kg a

a = 1.47 m/s²

Rounded to two significant figures, the block's acceleration is 1.5 m/s².

Usually the coefficient of static friction is greater than the coefficient of kinetic friction.  You might want to double check the problem statement, just to be sure.

6 0
4 years ago
If a 42kg rolling object slows from 11.5m/s to 3.33m/s how much work did friction do
geniusboy [140]

Answer: 1608.39 J

Explanation: Given that the

mass M = 42kg

U = 11.5m/s

V = 3.33m/s

how much work did friction do

Work done = Force × distance

Work done = Ma × distance

But acceleration a = V/t

Work done = M × V/t × d

Work done = M × V × d/t

Where d/t = velocity

Therefore,

Work done = M × U × V

Work done = 42 × 11.5 × 3.33

Work done = 1608.39 J

8 0
3 years ago
Which of the following must an engineer take into account when designing a roller coaster?
saveliy_v [14]

Answer:

The correct answer would be A

8 0
3 years ago
Joe is an athlete and ran today. His exercise heart rate is 130. His THRZ is 147-179
Katyanochek1 [597]

Answer:

The correct option is;

a) Mike, he is within his target heart rate zone

Explanation:

The Target Heart Rate Zone (THRZ) is the range of the percentage of a person's maximal heart beat rate (MHR) targeted to be achieved during exercising. It is a very good way to gauge the comparative intensity of a person's exercise

Whereby, Joe's heart beat rate is below his THRZ and Mikes heart beat rate is within his THRZ, Mike is working harder.

Hence the correct option is (a) Mike, he is within his target heart rate zone.

3 0
3 years ago
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