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Pavlova-9 [17]
3 years ago
9

A go-cart travels around a flat, horizontal,

Physics
2 answers:
ZanzabumX [31]3 years ago
8 0
♥ Centripetal force formula ⇒ mv^2/r
♥ Let's solve:
⇒1200/200=v^2/25
⇒1200*25/200=v^2
⇒v^2=150
⇒v=SQRT(150)
⇒=12.2
Keep in mind anything right after the carrot sign is considered a "exponent" or "to the power of."
<span>♥ Maximum speed it can go is 12m/s.</span>
ryzh [129]3 years ago
7 0
Centripetal force = mv^2/r

1200/200=v^2/25

1200*25/200=v^2
v^2=150
v=sqrt(150)=12.2

Therfore the maximum speed it can go is 12m/s.
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A 70-kg boy is sitting 3 m from the ground in a tree. What is his gravitational potential energy
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7 0
4 years ago
An airplane wing is designed so that the speed of the air across the top of the wing is 255 m/s when the speed of the air below
grin007 [14]
<h2>Answer:442758.96N</h2>

Explanation:

This problem is solved using Bernoulli's equation.

Let P be the pressure at a point.

Let p be the density fluid at a point.

Let v be the velocity of fluid at a point.

Bernoulli's equation states that P+\frac{1}{2}pv^{2}+pgh=constant for all points.

Lets apply the equation of a point just above the wing and to point just below the wing.

Let p_{up} be the pressure of a point just above the wing.

Let p_{do} be the pressure of a point just below the wing.

Since the aeroplane wing is flat,the heights of both the points are same.

\frac{1}{2}(1.29)(255)^{2}+p_{up}= \frac{1}{2}(1.29)(199)^{2}+p_{do}

So,p_{up}-p_{do}=\frac{1}{2}\times 1.29\times (25424)=16398.48Pa

Force is given by the product of pressure difference and area.

Given that area is 27ms^{2}.

So,lifting force is 16398.48\times 27=442758.96N

6 0
4 years ago
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