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mote1985 [20]
3 years ago
5

Which of the following is not a measurement taken by a radiosonde?

Physics
2 answers:
MariettaO [177]3 years ago
5 0

Correct answer choice is :


A) Atmospheric composition


Explanation:


A radiosonde is a battery-powered telemetry device transmitted into the environment normally by a weather balloon that regulates several atmospheric parameters and sends them by radio to a ground receiver. The radiosonde is a small, expandable device unit that is recessed below a six-foot-wide balloon inflated with hydrogen or helium. As the radiosonde stands at about 1,000 feet/minute, sensors on the radiosonde measure forms of pressure, temperature, and related moisture.

AlladinOne [14]3 years ago
4 0
I think the correct answer from the choices listed above is option A. Atmospheric composition is not a measurement taken by a radiosonde. A radiosonde is an instrument used to measure different atmospheric parameters.  
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What is the magnitude of the speed of a person at the equator due to rotational speed of the Earth?
notka56 [123]
The circumference of the Earth at the equator is listed as 24,901 miles.
So his speed is

                     24,901 miles per day.

Convert it to units that we have a better feel for:

                   (24,901 mi/da) x (1 da / 24 hrs)

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You'll find a huge number of people on the internet these days,
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4 0
3 years ago
A baseball leaves a bat with a horizontal velocity of 20.0 m/s. When it has left the bat for a time of 0.250 s (Assume air resis
miss Akunina [59]

Answer:

The distance is 5 m.

Explanation:

Given that,

Horizontal velocity = 20.0 m/s

Time t = 0.250 s

We need to calculate the horizontal distance

The distance traveled by the baseball with horizontal velocity in time t is given by

Using formula for horizontal distance

d = v\times t

d = 20.0\times0.250

d=5\ m

Hence, The distance is 5 m.

5 0
3 years ago
A 3.0kg weight W is initially at rest on incline AB, which is raised 40° above the horizontal. The effective coefficient is
lakkis [162]

(a) The acceleration of the system is determined as 1.58 m/s².

(b) The relative weight of P is pounds is determined as 0.14 lb.

<h3>Acceleration of the system</h3>

The acceleration of the system is calculated as follows;

W - T = m₂a --- (1)

T = m₁a ----(2)

μmgsinθ - m₁a = m₂a

(0.3 x 3 x 9.8 x sin40) - (0.4 + 0.2)a = 3a

5.67 - 0.6a = 3a

5.67 = 3.6a

a = 5.67/3.6

a = 1.58 m/s²

<h3> Relative Weight of P</h3>

W = ma

W = 0.4 x 1.58

W = 0.632 N = 0.14 lb

Learn more about weight here: brainly.com/question/2337612

#SPJ1

3 0
2 years ago
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