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kherson [118]
3 years ago
12

Match the adaptations with their benefits.Match the adaptations with their benefits.

Physics
2 answers:
laila [671]3 years ago
5 0
Wasp stinger protection from predators. Peacocks bright plumage to help obtain mate. Owls large eyes to help search for food. Bears fur to help maintain homeostasis
maw [93]3 years ago
5 0

Answer: the wasp’s stinger - protection against predators

the peacock’s bright plumage - attraction to obtain a mate

the owl’s large eyes - help to search for food

the bear’s fur - maintain homeostasis

Explanation:

An adaptation can be define as any change that occurs in the morphology, physiology and genetic make up of the organism which makes it suitable for survival in it's natural environment even in adverse conditions and reproduce.

The following are the adaptations with their benefits.

the wasp’s stinger - protection against predators

The wasp stinger generally exhibit toxic substance or allergy causing agent which the wasp use when it finds a predator around it.

the peacock’s bright plumage - attraction to obtain a mate

The male peacock exhibit bright and showy feathers which is a phenotypic advantage for attraction of female mates for copulation. This phenomena is called as sexual selection.

the owl’s large eyes - help to search for food

The owl's large eyes allows the night vision. There are many rods and cones present in the eyes of the owl so as to allow better vision in night and allow it to observe and capture prey.

the bear’s fur - maintain homeostasis

The bear's fur are insulating in nature that means it does not allow the entry of external air. Hence, helps in retaining the heat in the body in otherwise cold environment. Therefore, helps in maintaining the homeostasis (the tendency of the body retain it's constant internal environment as compared to changing external environment).

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Answer:

The speed of the sled is 9.2 m/s

The speed of the boulder is 0.82 m/s

Solution:

As per the question:

Mass of the boulder, m_{B} = 1000\ kg

Mass of the sled, m_{S} = 2.50\ kg

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Now,

To calculate the speed of both the sled and the boulder after the occurrence of the collision:

m = m_{b} + m_{S} = 40 + 2.50 = 42.50\ kg

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Since, the collision is elastic, both the energy and momentum rem,ain conserved.

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Using the conservation of momentum:

mv + m_{B}v_{B} = mv' + m_{B}v'_{B}

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v' = final velocity of the the system of boy and sled

v'_{B} = final velocity of the boulder

42.50\times 10 + m_{B}.0 = 42.50v' + 1000v'_{B}

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Now,

Using conservation of energy:

\frac{1}{2}mv^{2} + \frac{1}{2}m_{B}v_{B}^{2} = \frac{1}{2}mv'^{2} + \frac{1}{2}m_{B}v'_{B}^{2}

42.50\times 10^{2} + m_{B}.0 = 42.50v'^{2} + 1000v'_{B}^{2}

42.50v'^{2} + 1000v'_{B}^{2} = 4250         (2)

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v' = \frac{m - m_{B}}{m + m_{B}}\times v

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v'_{B} = \frac{2\times 42.50}{42.5 + 1000}\times 10 = 0.82\ m/s

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