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RideAnS [48]
3 years ago
6

(Math) Valentina purchased 200 beads for $48 to make necklaces. If she needs to buy 25 more beads, how much will she pay if she

is charged the same rate?
Mathematics
2 answers:
balandron [24]3 years ago
8 0

48/200=x/25 multiply both sides by 25 to get alone .  X=25+48/200. Then   X= 48/8. So x=6. Therefore she needs to pay $6 more  

Andrew [12]3 years ago
7 0

We can find the unit price for each bead by using 48/200.

48/200 = 0.24.

Valentina paid $0.24 for each bead.

Now, to find out how much it'd cost for 25 more, we can simply use 25 * 0.24.

25 * 0.24 = 6

Valentina will pay $6 for 25 more beads.

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Step-by-step explanation:

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The pie chart shows information about the voters in an election 2800 more women voted than men work out the total number of vote
Cerrena [4.2K]

The angle subtended by the women voters are 100° more than the angle subtended by the men voters.

  • The total number of voters are <u>10080 voters</u>

Reasons:

The angle subtended by the men on the pie chart = 130°

The number of women = 2800 + The number of men

Therefore;

Angle subtended by the women voters on the pie chart = 360° - 130° = 230°

The difference between the angle representing women and the angle

representing men = 230° - 130° = 100°

Therefore;

100° = 2800

Which by common ratios gives;

\dfrac{100^{\circ}}{360^{\circ}} = \dfrac{2800}{Total \ number \  of \ voters }

100 × Total number of voters = 2800 × 360

The \  total \  number  \ of  \ voters = \dfrac{2800 \times 360}{100}  = 10080

The total number of voters = <u>10080</u>

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A sample with a mean of m = 40 and a variance of s2 = 20 has an estimated standard error of 1 point. how many scores are in the
tamaranim1 [39]

The correct option is 20.

The score found for the sample is 20.

<h3>What is Standard error?</h3>

A standard error is a statistic that is applied to test the distribution of data. This metric is comparable to standard deviation. We can calculate the standard error if we know the sample size & standard deviation. It assesses the mean's precision.

Now, according to the question;

Sample mean; \bar{x}=40

Sample variance; s^{2}=20

Thus, s=\sqrt{20}=4.47

Standard error SE = 1

The amount of scores with in sample must be determined here.

The standard error formula is as follows:

S E=\frac{s}{\sqrt{n}}

We might rearrange the formula as follows:

\begin{aligned}\sqrt{n} &=\frac{s}{S E} \\n &=\left(\frac{s}{S E}\right)^{2}\end{aligned}

Substituting the values;

\begin{aligned}&n=\left(\frac{4.47}{1}\right)^{2} \\&n=19.98\end{aligned}

The sample's number of scores n = 19.98 = 20 (round up)

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