Ask question

Ask question

All categories

anastassius [24]

3 years ago

11

Over the past few years, Michael has increased his fee for mowing lawns from $5.00 per hour to $11.00 per hour. What percent did

Micael's fee increase?

1 answer:

Aleksandr-060686 [28]3 years ago

5 0

Answer:

120%

Step-by-step explanation:

Over the past few years, Michael has increased his fee for mowing lawns from $5.00 per hour to $11.00 per hour. What percent did Micael's fee increase?

The formula for Percentage increase is given as:

Increase/Initial amount × 100

Increase = New amount - Initial amount

From the above question, our increase = $11 - $5 = $6

Therefore,

Percentage increase = $6/$5 × 100

= 120%

Michael's fee increased by 120%

You might be interested in

The formula for finding the volume of a cone is V = 13πr2h. The volume of a cone is 300 cm3 and the height of the cone is 10 cm.

Kryger [21]

I think it would be B) 5cm

4 0

3 years ago

Solve the equation. \dfrac32 + b = \dfrac74 2 3 +b= 4 7 start fraction, 3, divided by, 2, end fraction, plus, b, equals, sta

Xelga [282]

Given:

The equation is

$\dfrac{3}{2}+b=\dfrac{7}{4}$

To find:

The value of b.

Solution:

We have,

$\dfrac{3}{2}+b=\dfrac{7}{4}$

Subtracting both sides by $\dfrac{3}{2}$ , we get

$b=\dfrac{7}{4}-\dfrac{3}{2}$

$b=\dfrac{7-2(3)}{4}$

$b=\dfrac{7-6}{4}$

$b=\dfrac{1}{4}$

Therefore, the value of b is $\dfrac{1}{4}$ .

3 0

3 years ago

Read 2 more answers

Help me please .......

kati45 [8]

Answer:

$\huge\boxed{\sf No}$

Step-by-step explanation:

<u>The ordered pairs for the given relation are:</u>

=> {(6,2)(-1,2)(-1,-1)(4,3)}

Domain => x-inputs of the ordered pairs

Domain => (6,-1,4)

Range => y-inputs of the ordered pairs

Range = (2,-1,3)

Since, <em>the values in the domain (-1) are being repeated, this relation is not a function.</em>

<em />

Hope this helped!

~AnonymousHelper1807

6 0

3 years ago

WILL GIVE BRAINLIEST, THANKS, AND 5 STARS!<br> PLEASE HELP ME!

Bogdan [553]

Answer:

-4 and 4

Step-by-step explanation:

<u>Method 1</u>

Apply Difference of Two Squares Formula: $a^2-b^2=(a+b)(a-b)$

Given $x^2-16=0$

Rewrite 16 as 4²

Therefore, $a^2=x^2$ and $b^2=4^2$

$\implies a = \sqrt{x^2}=x$

$\implies b=\sqrt{4^2} =4$

$\implies x^2-16^2=(x+4)(x-4)$

$\implies (x+4)(x-4)=0$

$\implies (x+4)=0 \implies x=-4$

$\implies (x-4)=0 \implies x=4$

<u>Method 2</u>

Given equation:

$x^2-16=0$

Add 16 to both sides:

$\implies x^2-16+16=0 + 16$

$\implies x^2=16$

Square root both sides:

$\implies \sqrt{x^2}=\sqrt{16}$

$\implies x=\pm4$

Therefore, x = -4, x = 4

6 0

2 years ago

Legit the last question I need someone help 20 points plus brinlyest

aleksandr82 [10.1K]

The fifth term would be seven

4 0

3 years ago

Read 2 more answers