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3 years ago

How many magazines at most can the company print daily,

Mathematics

1 answer:

Dvinal [7]3 years ago

6 0

Answer:

The most they can print is 800

Step-by-step explanation:

.5 N + 2.5M ≤ 6000

We are given N = 8000

Substitute this into the inequality

.5 (8000) + 2.5M ≤ 6000

4000 +2.5M≤ 6000

Subtract 4000 from each side

4000-4000 +2.5M≤ 6000 -4000

2.5M≤ 2000

Divide each side by 2.5

2.5M/2.5≤ 2000/2.5

M ≤800

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What is the total surface area of the figure shown?

4vir4ik [10]

Given:

Composite figure.

The figure splitted into two shapes.

One is vertical cuboid and other is horizontal cuboid

To find:

Total surface area of the figure

Solution:

<u>Vertical cuboid:</u>

Length = 14 inches

Width = 12 inches

Height = 24 inches

Surface area = 2(lw + wh + lh)

= 2(14 × 12 + 12 × 24 + 14 × 24)

= 2(168 + 288 + 336)

Surface area = 1584 square inches

<u>Horizontal cuboid:</u>

Length = 14 inches

Width = 10 inches

Height = 30 - 12 = 18 inches

Surface area = 2(lw + wh + lh)

= 2(14 × 10 + 10 × 18 + 14 × 18)

= 2(140 + 180 + 252)

Surface area = 1144 square inches

Total surface area = 1584 + 1144

= 2728 square inches

The total surface area of the figure is 2728 square inches.

4 0

3 years ago

How to factor 4(x+5)^3(x-1)^2-(x+5)^4 • 2 (x-1) by grouping?

nata0808 [166]

$\bf 4(x+5)^3(x-1)^2-(x+5)^4\cdot 2(x-1)
\\\\\\
4(x+5)^3(x-1)^2-2(x-1)(x+5)^4
\\\\\\ \underline{2}\cdot 2\underline{(x+5)^3}(x-1)\underline{(x-1)}~-~\underline{2}\underline{(x-1)}(x+5)\underline{(x+5)^3}\leftarrow 
\begin{array}{llll}
notice~the\\
common\\ \underline{factors}
\end{array}
\\\\\\
2(x+5)^3(x-1)~[~2(x-1)-(x+5)~]
\\\\\\
2(x+5)^3(x-1)~[2x-2-x-5]\implies 2(x+5)^3(x-1)(x-7)$

5 0

3 years ago

A pet store sells goldfish and hermit crabs,

Elis [28]

Answer:

$Cost = \$28$

Step-by-step explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:

$7g + 3h = 26$

The second statement, we have:

$4g + 5h = 28$

Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:

$7g + 3h = 26$ --- (1)

$4g + 5h = 28$ --- (2)

Make g the subject in (2)

$4g + 5h = 28$

$4g = 28 - 5h$

Divide both sides by 4

$g = \frac{1}{4}(28 - 5h)$

Substitute $\frac{1}{4}(28 - 5h)$ for g in (1)

$7g + 3h = 26$

$7(\frac{1}{4}(28 - 5h)) + 3h = 26$

$\frac{7}{4}(28 - 5h) + 3h = 26$

Multiply through by 4

$4 * \frac{7}{4}(28 - 5h) + 4*3h = 26*4$

$7(28 - 5h) + 4*3h = 26*4$

Open bracket

$196 - 35h + 12h = 104$

$196 -23h = 104$

Collect Like Terms

$-23h = 104-196$

$-23h = -92$

Make h the subject

$h = \frac{-92}{-23}$

$h = \frac{92}{23}$

$h = 4$

Substitute 4 for h in $g = \frac{1}{4}(28 - 5h)$

$g = \frac{1}{4}(28 - 5*4)$

$g = \frac{1}{4}(28 - 20)$

$g = \frac{1}{4}(8)$

$g = 2$

This implies that:

1 goldfish = $2

1 hermit crab = $4

The cost of 6 goldfish and 4 hermit crabs is:

$Cost = 6g + 4h$

$Cost = 6*\$2 + 4*\$4$

$Cost = \$12 + \$16$

$Cost = \$28$

5 0

3 years ago

In a figure, OB is the radius of a big semicircle and XB is the radius of the small semicircle. Given that OX = 14 cm, Calculate

oee [108]

Answer:

perimeter of the shaded region = 88 +44+28 =160 cm

Step-by-step explanation:

perimeter of shaded region = length AO + arc OB + arc AB

length AO = radius of bigger circle

radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm

therefore AO = 28 cm

length of arc oB= half of circumference of smaller circle = $\pi$ ×14 = 44 cm

length of arc ab = half of circumference of bigger circle = $\pi$ ×28 = $\frac{22}{7}$ ×28= 88

therefore perimeter of the shaded region = 88 +44+28 =160 cm

area of the shaded region = half of area of bigger circle - half of area of smaller circle

= $\frac{1}{2} \pi 28^{2} -\frac{1}{2} \pi 14^{2}$

= $\frac{\pi }{2} (28^{2} -14^{2} )$

solving we gen area of shaded region = 924

7 0

3 years ago

I don’t know how to do it

Alenkinab [10]

Answer:

u take 12 x 10=120+12=132 so the

answer is 132

4 0

3 years ago