<span>Center(0,0)
a^2=16
a=4
b^2=9
b=3
c^2=a^2+b^2=16+9=25
c=√25=5</span>
Answer:
6x^2
Step-by-step explanation:
Solutions
To solve the problem the first step is to m<span>ultiply the whole number by the fraction's denominator (4 x 3).Add the numerator (2) to the product.
4 * 3 = 12
12 + 2 = 14
= 14/3 </span>
Its a simultaneous equation:
lets make "x" the used games and "y" the new ones
4x + 2y = 84
6x + y = 78. (multiply this by 2 to cancel out y)
12x + 2y = 156
so now we subtract them:
12x - 4x = 156 - 84
x = 9
used games cost $9
new games cost 78 - 6(9) = $24
Janet has $120 but she already bought 3 NEW games so:
120 - 3(24) = $48 left
48/9 = how many used ones she can buy = 5. something
she can buy 5 used
