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ZanzabumX [31]
3 years ago
8

A bag contains 8 blue marbles, 6 green marbles, 12 yellow marbles, and 10 orange marbles. A marble is drawn at random from the b

ag.
What is the probability that the marble drawn will not be blue?

A.2/9

B.3/4

C.7/9

D.7/8
I was thinking either B or D
Mathematics
1 answer:
snow_tiger [21]3 years ago
7 0
Ok, so probablility of not drawing blue

total possible is 8+6+12+10=36

8 are blue so the total of not blue is 36-8=28

<span>so 28 out of 36=28/36=7/9 </span>
<span>the asnwer is 7/9 or C</span>
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P ( rolling a 5 or rolling a 4 ) on a die or fair number cube. Find the probability of these mutually exclusive events.​
pentagon [3]

Answer: I believe it the probability of this would be 1/3.

Step-by-step explanation: This is mainly because if the chances of rolling a 5 or a 4 on a die or fair numbered cube, which contains 6 sides, then landing on 5 or 4 would be 2 out of the six chances it would land on those two numbers. Hope this helps!

3 0
3 years ago
You have 2 job offers with the following options. Option 1: You are paid $30
kozerog [31]

Answer:

It takes 6 hours for both to reach an equal paid.

Step-by-step explanation:

You have to form an expressions in terms of x where x determine the number of hours :

Option 1,

$(30 + 9x)

Option 2,

$(14x)

Next, you have to compare it since they want to find out how many hours they work until they reach the same amount :

30 + 9x = 14x

30 = 14x - 9x

30 = 5x

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x = 30÷5

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8 0
3 years ago
Find the area of the figure. Round to the nearest tenth if necessary. 5.5 ft 6 ft 8 ft ​
bogdanovich [222]

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21 savage

Step-by-step explanation:

8 0
2 years ago
BD is the angle bisector of
AlexFokin [52]

Note: Let us consider, we need to find the m\angle ABC and m\angle DBC.

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The m\angle ABC and m\angle DBC.

Solution:

BD is the angle bisector of ABC. So,

m\angle ABD=m\angle DBC

3x=x+20

3x-x=20

2x=20

Divide both sides by 2.

x=\dfrac{20}{2}

x=10

Now,

m\angle DBC=(x+20)^\circ

m\angle DBC=(10+20)^\circ

m\angle DBC=30^\circ

And,

m\angle ABC=(3x)^\circ+(x+20)^\circ

m\angle ABC=(4x+20)^\circ

m\angle ABC=(4(10)+20)^\circ

m\angle ABC=(40+20)^\circ

m\angle ABC=60^\circ

Therefore, m\angle DBC=30^\circ,m\angle ABD=30^\circ and m\angle ABC=60^\circ.

8 0
2 years ago
I dont get this question, anyone help me please
prisoha [69]
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Hope you understand.
4 0
3 years ago
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