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BigorU [14]
4 years ago
11

Complete the following precipitation reaction with balanced molecular, total ionic, and net ionic equations. Remember to include

the proper physical states and charges of ions. When writing ions, if a charge number is not "1", place the charge number before the charge sign. If a charge number is "1", do not include the charge number in the formula. Na2S(aq) + ZnSO4(aq) →
Chemistry
1 answer:
LekaFEV [45]4 years ago
4 0

<u>Molecular equation (includes all species in the molecular form)</u>

Na₂S(aq) + ZnSO₄(aq) → Na₂SO₄(aq) + ZnS(s)

<u>Total ionic equation (includes all ions. Insoluble solids do not dissociate)</u>

2 Na⁺(aq) + S²⁻(aq) + Zn²⁺(aq) + SO₄²⁻(aq) → 2 Na⁺(aq) + SO₄²⁻(aq) + ZnS(s)

<u>Net ionic equation (includes only ions that participate in the reaction, that is, it does not include spectator ions)</u>

S²⁻(aq) + Zn²⁺(aq) → ZnS(s)

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If you have a neutral atom before joining, and it gains an electron to form a bond,<em> it will have one electron more than its initial state</em> (in the initial state, the number of protons and electrons is the same, because the atoms they are electrically neutral), so having an extra electron will make it have a negative charge, since there will be a difference between the number of protons and electrons that the atom possesses. <em>This is why the correct answer is D. </em>

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