Total = <span>products + reactants</span>
        
             
        
        
        
The mass of CO₂ gas = 4.312 g
<h3>Further explanation</h3>
Reaction
NaHCO₃ (s) + HCl (aq) → NaCl (aq) + H₂O (aq) + CO₂ (g)
Find limiting reactant
mol NaHCO₃ 

mol HCl

Limiting reactant :  NaHCO₃ (smaller)
mol CO₂ = mol NaHCO₃ = 0.098
mass CO₂ :

 
        
             
        
        
        
1) is right
2) lead(ii) phosphate
3) iron(iii)sulfate
4) lead(ii)oxide
5) lead sulfate
6) copper iodide
7) lead oxide
        
             
        
        
        
Answer: There are  moles
 moles  present in
 present in  particles.
 particles.
Explanation:
According to the mole concept, 1 mole of a substance contains  particles.
 particles.
Hence, number of moles present in  particles are calculated as follows.
 particles are calculated as follows.
No. of moles =  mol
 mol
                       =  mol
 mol
Thus, there are  moles
 moles  present in
 present in  particles.
 particles.
 
        
                    
             
        
        
        
Answer:
the answer is
the electronegativity of the elements from L to R increases