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3 years ago

IMMA WAIT FOR MY BABY EVEN IF IT TAKES ALL NIGHT !!!!!!

Chemistry

2 answers:

Lisa [10]3 years ago

8 0

Answer:

Oh ok

Explanation:

Also can u pls mark me brainliest im new pls

saul85 [17]3 years ago

3 0

Answer:

um okay lol

Explanation:

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What is the total pressure exerted by the mixture of gases only products or products + reactants?

dedylja [7]

Total = <span>products + reactants</span>

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3 years ago

Determine the mass of CO2 gas produced when 8.24 g of NaHCO3 is added to a solution that contains 4.41 g of HCl.

hjlf

The mass of CO₂ gas = 4.312 g

<h3>Further explanation</h3>

Reaction

NaHCO₃ (s) + HCl (aq) → NaCl (aq) + H₂O (aq) + CO₂ (g)

Find limiting reactant

mol NaHCO₃

$\tt \dfrac{8.24}{84,007 }=0.098$

mol HCl

$\tt \dfrac{4.41}{36.5}=0.121$

Limiting reactant : NaHCO₃ (smaller)

mol CO₂ = mol NaHCO₃ = 0.098

mass CO₂ :

$\tt 0.098\times 44=4.312~g$

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3 years ago

How do you name these compounds?

8090 [49]

1) is right
2) lead(ii) phosphate
3) iron(iii)sulfate
4) lead(ii)oxide
5) lead sulfate
6) copper iodide
7) lead oxide

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3 years ago

How many moles of dinitrogen tetroxide (N2O4) are in 6.49 x 109 particles?

yan [13]

Answer: There are $1.08 \times 10^{-14}$ moles $N_{2}O_{4}$ present in $6.49 \times 10^9$ particles.

Explanation:

According to the mole concept, 1 mole of a substance contains $6.022 \times 10^{23}$ particles.

Hence, number of moles present in $6.49 \times 10^9$ particles are calculated as follows.

No. of moles = $\frac{6.49 \times 10^9}{6.022 \times 10^{23}}$ mol

= $1.08 \times 10^{-14}$ mol

Thus, there are $1.08 \times 10^{-14}$ moles $N_{2}O_{4}$ present in $6.49 \times 10^9$ particles.

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2 years ago

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What is the trend in electronegativity as elements are considered from left to right in the periodic table?

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Answer:

the answer is

the electronegativity of the elements from L to R increases

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3 years ago