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hram777 [196]
3 years ago
11

Which of the following pieces of information about the element lithium describes the atomic number only

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
6 0
The top left corner shows the atomic number which is 3.
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In a simplified model of a hydrogen atom, the electron moves around the proton nucleus in a circular orbit of radius 0.53 × x10−
sergiy2304 [10]

the force between the electron and the proton.
a) Use F = k * q1 * q2 / d² 
where k = 8.99e9 N·m²/C² 
and q1 = -1.602e-19 C (electron) 
and q2 = 1.602e-19 C (proton) 
and d = distance between point charges = 0.53e-10 m 
The negative result indicates "attraction". 

the radial acceleration of the electron. 
b) Here, just use F = ma 
where F was found above, and 
m = mass of electron = 9.11e-31kg, if memory serves 
a = radial acceleration 

the speed of the electron. 
c) Now use a = v² / r 
where a was found above 
and r was given 

<span> the period of the circular motion.</span>
d) period T = 2π / ω = 2πr / v 
where v was found above 
and r was given 
3 0
3 years ago
Consider the following reaction:
Kitty [74]

Answer : The value of equilibrium constant (Kc) is, 0.0154

Explanation :

The given chemical reaction is:

                        SO_2Cl_2(g)\rightarrow SO_2(g)+Cl_2(g)

Initial conc.    2.4\times 10^{-2}          0             0

At eqm.          (2.4\times 10^{-2}-x)   x              x

As we are given:

Concentration of Cl_2 at equilibrium = 1.3\times 10^{-2}M

That means,

x=1.3\times 10^{-2}M

The expression for equilibrium constant is:

K_c=\frac{[SO_2][Cl_2]}{[SO_2Cl_2]}

Now put all the given values in this expression, we get:

K_c=\frac{(x)\times (x)}{2.4\times 10^{-2}-x}

K_c=\frac{(1.3\times 10^{-2})\times (1.3\times 10^{-2})}{2.4\times 10^{-2}-1.3\times 10^{-2}}

K_c=0.0154

Thus, the value of equilibrium constant (Kc) is, 0.0154

4 0
3 years ago
+ H20
Salsk061 [2.6K]

a. 2Na Al 03

Equation must have the same number of each element on both sides of the equation.

7 0
3 years ago
How many Mg atoms are presented in 3.00 moles of MgCl2
ella [17]

Answer:

1.81 x 10²⁴ atoms

Explanation:

To find the number of atoms in the given number of moles, we need to understand that every substance contains the Avogadro's number of particles.

More appropriately, a mole of any substance will contain the Avogadro's number of particles which is 6.02 x 10²³ atoms

 So;

           If 1 mole of a substance  = 6.02 x 10²³ atoms;

               3 mole of MgCl₂ will contain 3 x 6.02 x 10²³ = 1.81 x 10²⁴ atoms

3 0
3 years ago
Help brainliest plzzzz
konstantin123 [22]
The awnser is D or the 4th one
6 0
3 years ago
Read 2 more answers
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