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Gre4nikov [31]
4 years ago
12

How to find horizontal asymptotes with x as an exponent analytically?

Mathematics
1 answer:
tiny-mole [99]4 years ago
4 0
When the base is greater than 1, the value approaches zero as the exponent goes to -∞. When the base is less than 1, the value approaches zero as the exponent goes to ∞. Whatever additions or factors you have that modify the exponential term will modify the asymptote accordingly.
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Simplify the following expression into the form a + bi, where a and b are rational numbers.
alukav5142 [94]
I say 54



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3 0
3 years ago
Read 2 more answers
In the triangle, find x, y, u, v ​
Gwar [14]

Answer:

  • x = 9
  • y = 12
  • u = 24
  • v = 32

Step-by-step explanation:

Each of the triangles is similar, so we have ...

  3/5 = (3+x)/20

  x = 20(3/5) -3

  x = 9

__

  4/5 = (4+y)/20

  y = 20(4/5) -4

  y = 12

__

  3/5 = (3 + x + u)/60

  u = 60(3/5) -3 -9

  u = 24

__

  4/5 = (4 +y +v)/60

  v = 60(4/5) -4 -12

  v = 32

8 0
3 years ago
What is the area of the polygon below ​
Softa [21]

Answer:

It would be very difficult to determine the area without any given measurements of the sides. I'm afraid I cannot help you with this question.

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP 2 QUESTIONS 45 POINTS!!!!!!!!!
Effectus [21]

Answer:

1. -8x² - 16x - 6      a = -8, b = -16, c = -6

1. 4x² - 1                  a = 4, b = 0, c = -1

Step-by-step explanation:

use the 'foil' method:

(4x + 2)(-2x - 3)

F: -8x²     O: -12x       I: -4x       L: -6

-8x² - 16x - 6

(2x + 1)(2x - 1)

F: 4x²     O: -2x       I: 2x       L: -1

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5 0
3 years ago
A miners' cage of mass 420 kg contains 3 miners of total mass 280 kg. The cage
svp [43]

Answer:

5817 Newtons.

Step-by-step explanation:

Total mass of the cage + the miners = 700 Kg which is a downward force of  700g N.

The net downward force = 700g - T where T is the tension (force) in the cable. The g = acceleration due to gravity = 9.81 m s-2.

We  calculate the  acceleration of the cage by using an equation of motion:

Distance = ut + 1/2 a t^2     where u = initial velocity , t = time and a = acceleration:

75 = 0(t) + 1/2 a (10^2)

50a =  75

a = 1.5 m s-2.

So using Newtons second law of motion

Force = mass * acceleration:

700*9.81 - T = 700 * 1.5

T = 700 * 9.81 - 700*1.5

= 5817 N.

8 0
4 years ago
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