Answer:
Step-by-step explanation:
Let y be the number of lengths of the pool Lionel swam.
Given : Miguel swam 6 lengths of the pool .
Lionel swam as far as Miguel.
Then, the number of lengths Lionel swam :
Hence, the equation for how many lengths did Lionel swim will be :
If we simplify it , we get y= 2
Thus , Lionel swam 2 lengths of pool.
Lionel = (1/3)(6 lengths)
The problem statement tells us that Lionel swam 1/3 as far as the 6 lengths that Miguel swam. Lionel's distance can be found from the equation ...
No, you don't.
The denominator only changes if you're multiplying/dividing. You may need to create an <em>equivalent fraction</em> to add the fractions together, but you <em>don't</em> add or subtract the denominator.
Hope this helps! Have a great day!
About $6805.66 as I rounded it up
For this case, we must clear variable "x" from the given equation, expressed in terms of "a".
We have:
3/a x-4=20
By clearing "x" we have:
Adding 4 to both sides of the equation:
3/a x = 20 + 4
Multiplying by a/3 on both sides of the equation:
x=24a/3
x=8a
So, x=8a
the answer to this question is 52.18