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choli [55]
3 years ago
8

The heat of fusion for water is 80. cal/g. how many calories of heat are released

Chemistry
1 answer:
Ray Of Light [21]3 years ago
7 0

800 calories are released


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I need the 3 questions !!! About Rubidium (Rb) <br><br> ASAP PLEASE DUE IN LIKE 20 min
hjlf

Answer:

  1. 419kJ/mol  
  2. 5,0,0,+12
  3. That catches fire spontaneously

Explanation:

1. Topic: Chemistry

ElementFirst Ionization Energy (kJ/mol) Lithium520Sodium496Rubidium403Cesium376According to the above table, which is most likely to be the first ionization energy for potassium?  

  • 536kJ/mol  
  • 504kJ/mol  
  • 419kJ/mol  
  • 391kJ/mol  
  • 358kJ/mol

2. Topic: Chemistry, Atom

The correct set of four quantum numbers for the valence electrons of the rubidium atom   (Z=37)  is:  

  • 5,1,1,+12  
  • 5,0,1,+12  
  • 5,0,0,+12
  • 5,1,0,+12

3. Rubidium and cesium are pyrophoric. Here the term pyrophoric means:

  • That hardly catches fire
  • That does not catch fire at all
  • That catches fire spontaneously
  • None of these
5 0
3 years ago
Plz help for chemistry quiz I’ll mark brainliest
zvonat [6]

Answer: All of these answers are sorrect

ExplanationA scientist does all of these things while operforming a experiment

4 0
3 years ago
Which is stronger- the attractive forces between water molecules and chromium and chloride ions, or the combined ionic bond stre
Nutka1998 [239]

Answer:

When chromium chloride, CrCl2, is dissolved in water, the temperature of the water decreases. ... The attractive forces between water molecules and chromium and chloride ions is stronger, because the reaction is endothermic means the energy released in formation is less than the energy required in breaking bond.

6 0
3 years ago
I need help! FAST!!!​
aliina [53]

Answer:

The second answer choice

Explanation:

X seems to list attributes for opaque objects, and y lists attributes of Transparent objects.

5 0
3 years ago
Calculate the mass of calcium chloride that contains 3.20 x 1024 atoms of chlorine.
frez [133]

Answer:

294.87 gm  CaCl_2

Explanation:

The computation of the  mass of calcium chloride is shown below:

But before that following calculations need to be done

Number of moles of chlorine atom is

= 3.20 × 10^24 ÷ 6.022 × 10^23

= 5.314 moles

As we know that

1 mole CaCl_2 have the 2 moles of chlorine atoms

Now 5.341 mole chloride atoms would be

= 1 ÷ 2 × 5.314

= 2.657 moles

Now

Mass of CaCl_2 = Number of moles × molar mass of  CaCl_2

= 2.657 moles × 110.98 g/mol

= 294.87 gm  CaCl_2

7 0
3 years ago
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