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Art [367]
2 years ago
8

What is the answer? plz give me the right answer which you are sure of .

Chemistry
1 answer:
alisha [4.7K]2 years ago
8 0
Mention four reasons why the poll ordinance failed
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A scientist collected the data shown in the graph above. How is the graph useful to the scientist?
Vladimir79 [104]
The scientist can analyze that data and help other scientists with his research
7 0
3 years ago
What are table sugar and baking soda examples of
schepotkina [342]

Answer:

Examples of pure substances include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and baking soda (sodium bicarbonate). Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances that are chemical elements. All elements are pure substances.

Explanation:

PLEASE MARK ME AS BRAINLIEST

4 0
2 years ago
Which of the following are not single-displacement reactions?
Goshia [24]

Answer:

\boxed{\text{B and C }}

Explanation:

In a single-displacement reaction, one element exchanges partners with another element in a compound.

\textbf{A. } \rm Fe + 2HCl \longrightarrow FeCl_2 + H_2

This is a single-displacement reaction, because the element Fe exchanges partners with H in HCl.

\textbf{B. } \rm KOH + HNO_3 \longrightarrow H_2O + KNO_3

This is not a single-displacement reaction, because it is a reaction between two compounds.

This is a double displacement reaction in which the K⁺ and H⁺ cations change partners with the anions.

\textbf{C. } \rm Na_2S + 2HCl \longrightarrow 2NaCl + H_2S

This is not a single-displacement reaction. It is another double displacement reaction, in which the Na⁺ and H⁺ cations change partners with the anions.

\textbf{D. } \rm Ca + 2HOH \longrightarrow Ca(OH)_2 + H_2

This is a single-displacement reaction, because the element Ca exchanges partners with H in H₂O.

\boxed{\textbf{B and C }} are not single-displacement reactions.

6 0
3 years ago
How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 4.46 atm and 45°C in the reaction shown below?
natka813 [3]

Answer:

8.1433 g of XeF₆  are required.

Explanation:

Balanced chemical equation;

XeF₆ (s) + 3H₂ (g)   →  Xe (g) + 6HF (g)

Given data:

Volume of hydrogen = 0.579 L

Pressure = 4.46 atm

Temperature = 45 °C (45+273= 318 k)

Solution:

First of all we will calculate the moles of hydrogen

PV = nRT

n = PV/ RT

n = 4.46 atm × 0.579 L / 0.0821 atm. dm³. mol⁻¹. K⁻¹ × 318 K

n = 2.6 atm . L / 26.12 atm. dm³. mol⁻¹

n = 0.0995 mol

Mass of hydrogen:

Mass = moles × molar mass

Mass =  0.0995 mol × 2.016 g/mol

Mass =  0.2006 g

Now we will compare the moles of hydrogen with XeF₆ from balance chemical equation.

                                         H₂   :  XeF₆

                                          3    :    1

                                 0.0995   : 1/3× 0.0995 = 0.0332 mol

Now we will calculate the mass of XeF₆.

Mass = moles × molar mass

Mass = 0.0332 mol × 245.28 g/mol

Mass = 8.1433 g

4 0
3 years ago
Check if these are right please, and correct me on any of them:
TiliK225 [7]
I believe those all look correct!

4 0
3 years ago
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