Explanation:
Fe2o3+ 3co ---------. 2fe + 3co2
Answer:
27.3 kJ/mol
Explanation:
Step 1: Given data
- Temperature 1 (T₁): 298 K
- Vapor pressure 1 (P₁): P₁
- Temperature 2 (T₂): 318 K
- Vapor pressure 2 (P₂): 2 P₁
Step 2: Calculate the enthalpy of vaporization of this liquid
We will use the Clausius–Clapeyron equation.
ln (P₂/P₁) = -ΔHvap/R × (1/T₂ - 1/T₁)
ln 2 = -ΔHvap/(8.314 J/K.mol) × (1/318 K - 1/298 K)
ΔHvap = 2.73 × 10⁴ J/mol = 27.3 kJ/mol
Answer:
One other factor is the number of electrons removed. The potassium atom has one electron removed to for the corresponding ion, while calcium loses two electrons. The addition of electrons always results in an anion that is larger than the parent atom.
The easiest way to answer this question is to first figure out the molar mass of the sugar in question. To do this multiply the number of individual atoms for a given element by its atomic mass. 12 X 12.01 g/mol = 144.12 g/mol C. 22 X 1.008 g/mol = 22.176 g/mol H. 11 X 16.00 g/mol = 176.00 g/mol O.