Answer:
The molar mass and atomic mass are essentially the same for an element
Explanation:
The molar mass of a substance can be obtained by dividing the mass of the substance by the no of moles of the substance present.
The atomic mass of an element is the number of protons and neutrons present in the substance.
These two measurements usually give the same values because they both make reference to the 1/12th the mass of carbon-12 for their measurement.
Because they both have the same reference point, though they have different calculating procedures, the results obtained will be similar.
The answer originally came out as 11.36 but if you are supposed to be rounding then your answer should be 11.4
Answer/Explanation:
<u>Acids:</u>
Physical ⇒ Sour Taste, Increases the concentration of hydrogen ions when added to water
Chemical ⇒ Corrosive (Burns your skin and breaks down other materials), Forms hydrogen gas when it comes in contact with a metal, Forms salt and water when added to a base
Example: Tomatoes
<u>Bases:</u>
Physical ⇒ Bitter taste ( Never taste or smell a substance unless your parent/guardian tells you that it is okay), Slippery feeling(never touch a substance unless your parent/guardian tell you that is okay)
Chemical ⇒ Increases the concentration of hydroxide ions when added to water, Forms salt and water when added to an acid
Example: Soap, Clorox
[RevyBreeze]
Answer:
The average atomic mass of bromine is 79.9 amu.
Explanation:
Given data:
Percentage of Br⁷⁹ = 55%
Percentage of Br⁸¹ = 45%
Average atomic mass of bromine = ?
Formula:
Average atomic mass = [mass of isotope× its abundance] + [mass of isotope× its abundance] +...[ ] / 100
Now we will put the values in formula.
Average atomic mass = [55 × 79] + [81 ×45] / 100
Average atomic mass = 4345 + 3645 / 100
Average atomic mass = 7990 / 100
Average atomic mass = 79.9 amu
The average atomic mass of bromine is 79.9 amu.
Answer:- D)
particles
.
Solution:- There are 1.53 moles of the compound are given and it asks to calculate the number of particles.
To calculate the number of particles we multiply the moles with Avogadro number.
![1.53mol(\frac{6.022*10^2^3particles}{1mol})](https://tex.z-dn.net/?f=1.53mol%28%5Cfrac%7B6.022%2A10%5E2%5E3particles%7D%7B1mol%7D%29)
= ![9.21*10^2^3](https://tex.z-dn.net/?f=9.21%2A10%5E2%5E3)
So, the D is the right choice.