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likoan [24]
4 years ago
9

The function​ s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237. Find the a

verage velocity of the object over the interval of time [1, 3].
Mathematics
1 answer:
trapecia [35]4 years ago
5 0

Answer:

29 is answer.

Step-by-step explanation:

Given that the function​ s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237.

To find average velocity of the object over the interval of time [1,3]

We know that derivative of s is velocity and antiderivative of velocity is position vector .

Since moving along a line equation of s is

use two point formula

\frac{s-150}{237-150} =\frac{t-2}{5-2} \\s=29t-58+150\\s=29t+92 gives the position at time t.

Average velocity in interval (1,3)

=\frac{1}{3-1} (s(3)-s(1))\\=\frac{1}{2} [87+58-29-58]\\=29

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Since there are 360^{\circ} in a circle, and central \angle AOB = 90^{\circ}, you can see that the part "sliced out" by the central angle is \frac{90^{\circ}}{360^{\circ}} = \frac{1}{4} of the whole circle.

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djverab [1.8K]

Answer:

Step-by-step explanation:

The area of each rectangle is Length x width

Therefore Area of rectagle is 8cm x 10 cm=

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