Question

Evaluate the expression for the given values: 2x^2 _8xy+3y^2 for x = -3 and y = 2

Answer 1

Answer:

Value = 78

Step-by-step explanation:

We replace the values, x = -3 and y = 2, so:

$2x^{2} -8xy+3y^{2} =2(-3)^{2}-8(-3)(2)+3*2^{2}=2*9+48+3*4=18+48+12=78$