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2 years ago

Evaluate the expression for the given values: 2x^2 _8xy+3y^2 for x = -3 and y = 2

Mathematics

1 answer:

Ganezh [65]2 years ago

5 0

Answer:

Value = 78

Step-by-step explanation:

We replace the values, x = -3 and y = 2, so:

$2x^{2} -8xy+3y^{2} =2(-3)^{2}-8(-3)(2)+3*2^{2}=2*9+48+3*4=18+48+12=78\\$

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7 times a number is 18 less than the square of that number. Find the positive solution.

Arte-miy333 [17]

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Step-by-step explanation:

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Diano4ka-milaya [45]

Answer:

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Step-by-step explanation:

step 1

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we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

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substitute in the formula above

$A=2,250(1+0.04*10)$

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step 2

Interest compounded annually

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1$

substitute in the formula above

$A=2,250(1+\frac{0.04}{1})^{1*10}$

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step 3

Find the differences between the two final amounts

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Step-by-step explanation:

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