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3 years ago

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5 times the difference of 29 and a number is 215. Which equation below can be used to find the unknown number?

2 answers:

Verdich [7]3 years ago

8 0

Is it multiple choice? If not I would say 215=5(x)-29

Ilia_Sergeevich [38]3 years ago

3 0

Answer:

The required equation is $5(29-n)=215$

Step-by-step explanation:

Given : 5 times the difference of 29 and a number is 215.

To find : Which equation can be used to find the unknown number?

Solution :

Let the number be 'n'.

The difference of 29 and a number i.e. $29-n$

5 times the difference of 29 and a number i.e. $5(29-n)$

5 times the difference of 29 and a number is 215 i.e. $5(29-n)=215$

Therefore, the required equation is $5(29-n)=215$

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A normal population has a mean of 19 and a standard deviation of 5.

dangina [55]

Answer:

a) $Z = 1.2$

b) 38.49% of the population is between 19 and 25.

c) 34.46% of the population is less than 17.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. If we need to find the probability that the measure is larger than X, it is 1 subtracted by this pvalue.

For this problem, we have that

A normal population has a mean of 19 and a standard deviation of 5, so $\mu = 19, \sigma = 5$ .

(a) Compute the z value associated with 25

This is Z when $X = 25$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 19}{5}$

$Z = 1.2$

(b) What proportion of the population is between 19 and 25?

This is the pvalue of Z when $X = 25$ subtracted by the pvalue of Z when $X = 19$ .

X = 25 has $Z = 1.2$ , that has a pvalue of 0.8849.

X = 19 has $Z = 0$ , that has a pvalue of 0.5000.

So 0.8849-0.500 = 0.3849 = 38.49% of the population is between 19 and 25.

(c) What proportion of the population is less than 17?

This is the pvalue of Z when $X = 17$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{17 - 19}{5}$

$Z = -0.40$

$Z = -0.40$ has a pvalue of 0.3446.

This means that 34.46% of the population is less than 17.

7 0

3 years ago

Pete is a politician. He claims that 32% of the households in his district have total household incomes below the poverty level.

victus00 [196]

Answer:

$z=\frac{0.3867 -0.32}{\sqrt{\frac{0.32(1-0.32)}{225}}}=2.145$

For a bilateral test the p value would be:

$p_v =2*P(z>2.145)=0.0320$

Step-by-step explanation:

Information given

n=225 represent the sample selected

X=87 represent the households with incomes below the poverty level

$\hat p=\frac{87}{225}=0.3867$ estimated proportion of households with incomes below the poverty level

$p_o=0.32$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to check if the true proportion is equal to 0.32 or not.:

Null hypothesis: $p=0.32$

Alternative hypothesis: $p \neq 0.32$

The statistic is given bY:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.3867 -0.32}{\sqrt{\frac{0.32(1-0.32)}{225}}}=2.145$

For a bilateral test the p value would be:

$p_v =2*P(z>2.145)=0.0320$

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4 years ago

The youth group is going on a trip to the state fair. The trip costs $58. Included in that price is $12 for a concert ticket and

Ksivusya [100]

2x + 12 = 58 <== ur equation (cost of the trip)
2x = 58 - 12
2x = 46
x = 46/2
x = 23 <== price of 1 pass

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nordsb [41]

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