The angular velocity, ω=
2π/t; t = 24 hrs = 24 x 3600 seconds = 86400 s
ω = 7.27 x 10⁻⁵
v = ωr
= 7.27 x 10⁻⁵ x 3242.8 x 1.6 x 1000 (converting miles to meters)
= 377.2 m/s
To solve this problem we will apply the concepts related to the relationship between the voltage, the electric field and the distance, once the voltage is found we will use the definition of power, which is defined as the square of the voltage over the resistance. This is,

E = Electric field
d= Distance between the points
Replacing,


Now applying the relation for power we have,

Here
V = Voltage
R = Resistance
Replacing,


Therefore the total power emmited by the transmitter is 224509.3 W
Answer:
s = 0.337 m
Explanation:
First, we will find the angular displacement of the reel:

where,
θ = angular displacement = ?
ω = angular speed = 1.9 rad/s
t = time taken = 7.1 s
Therefore,
θ = (1.9\ rad/s)(7.1 s)
θ = 13.5 rad
Now, we will find out the length of tape:
s = rθ
where,
s = length of tape = ?
r = radius of reel = 2.5 cm = 0.025 m
Therefore,
s = (0.025 m)(13.5 rad)
<u>s = 0.337 m</u>
Let's say the velocity at the bottom of the window was "v."
s = v*t + ½at²
2 m = v * 1.3s - 4.9m/s² * (1.3s)² = v * 1.3s - 8.3 m
v = 10.3m / 1.3s = 7.9 m/s
Then the initial speed was
V = √(v² + 2as) = √(7.9m/s² + 2 * 9.8m/s² * 7.5m) = 14 m/s ◄ initial velocity
(after rounding to 2 digits from 14.5 m/s).