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3 years ago

Question 1 and 2 and 3 physics lesson homework

Physics

1 answer:

storchak [24]3 years ago

5 0

Answer:

Jackson 2: Smart 3: Ahmed

Explanation:

square + circle = egg

oops, wrong guy

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Two truckers are traveling directly away from each other at the same speed. If one trucker sounds her horn at a frequency of 221

8_murik_8 [283]

Answer:

v = 8.8 m /s

Explanation:

For listener and source going away from each other the formula of Doppler effect is as follows

$\frac{f}{f_0} = \frac{V-v}{V+v}$

V is velocity of sound , v is velocity of listner and source of sound

f₀ is apparent frequency and f is real frequency

V = 343 , v = ? ,f = 210 , f₀ = 221

Put these value in the relation above

$[tex]\frac{210}{221} = \frac{343-v}{343+v}$ [/tex]

v = 8.8 m /s

6 0

3 years ago

a golfer hits a golf ball with a velocity of 36.0 meters/second at an angle of 28.0. if the hang time of the golf ball is 33.4 s

Kobotan [32]

Solving this using the time, we know that range = horizontal velocity x time of flight

since there are no horizontal forces acting on the ball, there are no horizontal accelerations and the initial horizontal velocity of 36 cos 28 will be constant throughout. If we use the correct time of flight given the launch parameters, we have

range = 36 cos 28 x 3.44 s = 109.3 m

6 0

3 years ago

An unstoppable object is heading right toward an unmovable object. What's going to happen?

marshall27 [118]

Answer:

In my opinion the unstoppable object will hit the unmovable object and stop but the wheels will still be rolling and trying to move but can't.

<h3>Hope this helps.</h3><h3>Good luck ✅.</h3>

8 0

2 years ago

If a certain shade of blue has a frequency of 7.33 x 10^14Hz what is the energy of exactly one photon of this light. Is this as

geniusboy [140]

In calculating the energy of a photon of light, we need the relationship for energy and the frequency which is expressed as:

E=hv

where h is the Planck's constant (6.626 x 10-34 J s)and v is the frequency.
E = 6.626 x 10-34 J s (<span>7.33 x 10^14 /s) = 4.857 x 10^-19 J</span>

6 0

4 years ago

The leaves of a tree lose water to the atmosphere via the process of transpiration. A particular tree loses water at the rate of

Gnoma [55]

Answer:

The speed of the sap flowing in the vessel is 1.90 mm/s

Explanation:

Given:

The rate of water loss, Q = 3 × 10 ⁻⁸ m³/s

Number of vessels contained, n = 2000

Diameter of the vessel, D = 100 Mu m

thus, the radius of the vessel, r = 50 × 10⁻⁶ m

Now, the rate of flow is given as:

Q = AV .............(1)

where, A is the area of the cross-section

V is the velocity

Total area, A = n × (πr²)

substituting the values in the equation (1), we get

3 × 10 ⁻⁸ m³/s = [2000 × (π × (50 × 10⁻⁶)²)] × V

V = 1.909 × 10⁻³ m/s or 1.90 mm/s

Hence, the speed of the sap flowing in the vessel is 1.90 mm/s

7 0

3 years ago