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aleksklad [387]
3 years ago
10

The earth rotates about its pole once every 24 hrs. The distance from the pole to a location on the Earth is 35* north latitude

is about 3243.8 miles. Therefore, a location on Earth at 35* north latitude is spinning on a circle of radius 3242.8 miles. Compute the linear speed on the surface of the Earth at 35* north latitude.
Physics
1 answer:
Oksana_A [137]3 years ago
4 0
The angular velocity, ω= 
2π/t; t = 24 hrs = 24 x 3600 seconds = 86400 s
ω = 7.27 x 10⁻⁵
v = ωr
= 7.27 x 10⁻⁵ x 3242.8 x 1.6 x 1000 (converting miles to meters)
= 377.2 m/s
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Volgvan

Answer:

The height is : 60.025 m

Explanation:

The flowerpot falls off the balcony with zero launch angle

Given the time of fright as 3.5 s then ;

The formula to apply is ;

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3.5²= 2H/9.8

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Answer:

<em>d. 268 s</em>

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<u>Constant Speed Motion</u>

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Expressed in a simple equation, we have:

\displaystyle v=\frac{d}{t}

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