Answer:
The terms used to describe the given process in <em><u>Chemical weathering.</u></em>
Explanation:
Weathering of rock is defined as breaking down of the rock into small pieces.
There are two types pf weathering :
Mechanical weathering : This weathering is due to change in physical parameters : temperature change, pressure change etc.
For example : When water soaked up in cracks or crevices of rocks freezes it expands and physically breaks the rock.
Chemical weathering : This weathering is decomposition of rocks due to action of chemicals.This type of weathering also changes chemical composition of rocks.
For example : when gases like carbon dioxide, sulfur oxide get dissolves in water present in rock to form weak acid which ease up the dissolving of rock in that weak acid.
Protium - the most common isotope of hydrogen - has no neutrons in its nucleus.
I recommend this channel called "Crash Course" on youtube and he has a playlist full of chemistry videos he makes it very fun & very easy to understand. Another option i recommend is researching chemistry on this website called "Khan academy" i did and it helped me alott!!
2SO₂+O₂⇒2SO₃ ΔH=-197 kJ
<h3>Further explanation</h3>
Based on the principle of Hess's Law, the change in enthalpy of a reaction will be the same even though it is through several stages or ways
Reaction
2SO₂+O₂⇒2SO₃
Given :
1. S(s)+O₂(g)→SO₂(g) ΔH = -297 kJ
Reverse
SO₂(g) ⇒S(s)+O₂(g ΔH = +297 kJ
(sign change to +) x 2
2SO₂(g) ⇒2S(s)+2O₂(g ΔH = +594 kJ
2.2S(s)+3O2(g)→2SO3(g) ΔH=-791kJ
Add both reactions and remove/subtract the same compound for different sides
1. 2SO₂(g) ⇒2S(s)+2O₂(g) ΔH = +594 kJ
2.2S(s)+3O₂(g)→2SO₃(g) ΔH=-791kJ
--------------------------------------------------------+
2SO₂+O₂⇒2SO₃ ΔH=-197 kJ
As we know that
P.E. = mgh
where,
P.E. = Potential energy of the object =?
m= mass of object= 3kg
g= acceleration due to gravity = 9.8 ms^-2
h = height between object and animal = 0 m
Then
P.E. = 3× 9.8 × 0 = 0 Joules or 0J
<em>Have a luvely day!</em>
