Answer is All of the above
The mole fraction of KCl = 0.105
<h3>Further explanation</h3>
Given
%w/w KCl = 32.7
Required
the mole fraction of KCI
Solution
For 100 g solution : KCl = 32.7 g, H₂O = 67.3 g
mol KCl :
mol H₂O :
total mol of solution = 0.439+3.74=4.179
mol fraction of KCl :
Answer:
In your case, you have 8 protons and 10 electrons. This means that the atom will carry a total 2 xx (1-) = 2- net charge. Therefore, you are dealing with an anion that carries a 2- net charge, i.e. it has two more electrons than it does protons.
Wouldn't it be 100? 150 - 50 would equal 100. Unless I'm not seeing something.
To answer this item, we assume that oxygen behaves ideally such that it is able to fulfill the following equation,
PV = nRT
If we are to retain constant the variable n and V.
The percent yield can therefore be solved through the following calculation,
n = (10.5 L)/(22.4 L) x 100%
Simplifying,
n = 46.875%
Answer: 48.87%